P
praveen
Guest
Hello Mr. Meindert,
Thanks for the reply.
About maximum temperature rise:
Thermal resistance =150 K/w (50+100)
So temperature rise= 114 K so it means 50 C increase in temperature.
So junction temperature is around 80 c which very much below the
juction temperature (150 c). About the drive voltage higher FET has
around 35-40 V and lower 8-10 V.
Please correct me if i am wrong.
Is there some thing which i am missing???
Is have not provided any heat sink. My boss is not agreeing with any
PCB changes. If it is very much require i have to convince him.
It need your feedback from you people.
Thanks and regards
Praveen
Thanks for the reply.
About maximum temperature rise:
Thermal resistance =150 K/w (50+100)
So temperature rise= 114 K so it means 50 C increase in temperature.
So junction temperature is around 80 c which very much below the
juction temperature (150 c). About the drive voltage higher FET has
around 35-40 V and lower 8-10 V.
Please correct me if i am wrong.
Is there some thing which i am missing???
Is have not provided any heat sink. My boss is not agreeing with any
PCB changes. If it is very much require i have to convince him.
It need your feedback from you people.
Thanks and regards
Praveen