Memory sdram

[Dave]

Can someone explain me below memory organizations???
Dave.

64 Meg x 4 (16 Meg x 4 x 4 banks)
does above ic have 64 megabytes in 16 banks or have 256 megabytes or it
is in megabits?


32 Meg x 8 ( 8 Meg x 8 x 4 banks)
16 Meg x 16 ( 4 Meg x 16 x 4 banks)

 

[Impmon]

On Sat, 15 Nov 2003 14:49:44 +0100, Dave <davecle@SoftHome.net> typed:

64 Meg x 4 (16 Meg x 4 x 4 banks)
does above ic have 64 megabytes in 16 banks or have 256 megabytes or it
is in megabits?

Often time when I hear the term "Meg" it is in Megabit. Although it has
4 bit addresses, it also has 4 banks so the controller could view this
as 2 banks of 8 bit. Of course I could be wrong as some memory
manufactures don't always have the uniform standards for reading codes.

So 16 x 4 x 4 would be 256 Megabit or 32 Megabyte.

32 Meg x 8 ( 8 Meg x 8 x 4 banks)

Also 32 Megabyte.

16 Meg x 16 ( 4 Meg x 16 x 4 banks)

And 32 as well.
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[Fabricio]

32 Meg x 8 ( 8 Meg x 8 x 4 banks)
16 Meg x 16 ( 4 Meg x 16 x 4 banks)

- PC SDRAM DIMM -

Example:
(capacity of the each IC) x (Nş of ICs on the module) / 8 (bits per
byte) = Capacity of the Module in Megabytes

32Mbits x 8 ICs / 8 = 32Mbytes (256Mbits) (Single-Sided / 1-bank)

16Mbits x 16 ICs / 8 = 32Mbytes (256Mbits) (Double-Sided / 2-bank)

The number of ICs per module always is a multiple of 8 (8, 16, etc)

--
Fabricio