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Multiply the drop across one LED by the number in series (e.g., 2 V x 6 = 12I have used LED's many times before but never in series.
I need to run as many LED's as possible from a 12v supply. Is there a
formula for series LED connections ?
Cheers for the help. I have not been ignoring you, my PC decided to clean up"Norman" <stayforthedayandgo@yahoo.com> wrote in message
news:a4cji.129081$hj5.101518@fe2.news.blueyonder.co.uk...
I have used LED's many times before but never in series.
I need to run as many LED's as possible from a 12v supply. Is there a
formula for series LED connections ?
Multiply the drop across one LED by the number in series (e.g., 2 V x 6 =
12 V) up to the limit of the supply. However, it is better to leave a
couple of volts for a series resistor. So, you could connect 5 in series
with a 100 ohm resistor. Even better, use a constant current supply with
a compliance voltage range large enough to forward bias all of the diodes.
Short of looking at the specifications for your particular LED, let's"Charles" <charlesschuler@comcast.net> wrote in message
news:2cadnVWCkP_zyRDbnZ2dnUVZ_u-unZ2d@comcast.com...
"Norman" <stayforthedayandgo@yahoo.com> wrote in message
news:a4cji.129081$hj5.101518@fe2.news.blueyonder.co.uk...
I have used LED's many times before but never in series.
I need to run as many LED's as possible from a 12v supply. Is there a
formula for series LED connections ?
Multiply the drop across one LED by the number in series (e.g., 2 V x 6 =
12 V) up to the limit of the supply. However, it is better to leave a
couple of volts for a series resistor. So, you could connect 5 in series
with a 100 ohm resistor. Even better, use a constant current supply with
a compliance voltage range large enough to forward bias all of the diodes.
Cheers for the help. I have not been ignoring you, my PC decided to clean up
my news massages and I cant get them back.
Reading your suggestion I am guessing that the 100 ohm resistor is enough to
lose 2 volts.
eg. if my final voltage is 14 volts, I can get away with 6 leds and a 100
ohm res ?
Also guessing I needs to know if the leds want 2v or 1.6 / 1.8v ?
On Wed, 18 Jul 2007 17:20:33 +0100, "Norman"
stayforthedayandgo@yahoo.com> wrote:
"Charles" <charlesschuler@comcast.net> wrote in message
news:2cadnVWCkP_zyRDbnZ2dnUVZ_u-unZ2d@comcast.com...
"Norman" <stayforthedayandgo@yahoo.com> wrote in message
news:a4cji.129081$hj5.101518@fe2.news.blueyonder.co.uk...
I have used LED's many times before but never in series.
I need to run as many LED's as possible from a 12v supply. Is there a
formula for series LED connections ?
Multiply the drop across one LED by the number in series (e.g., 2 V x 6
=
12 V) up to the limit of the supply. However, it is better to leave a
couple of volts for a series resistor. So, you could connect 5 in
series
with a 100 ohm resistor. Even better, use a constant current supply
with
a compliance voltage range large enough to forward bias all of the
diodes.
Cheers for the help. I have not been ignoring you, my PC decided to clean
up
my news massages and I cant get them back.
Reading your suggestion I am guessing that the 100 ohm resistor is enough
to
lose 2 volts.
eg. if my final voltage is 14 volts, I can get away with 6 leds and a 100
ohm res ?
Also guessing I needs to know if the leds want 2v or 1.6 / 1.8v ?
Short of looking at the specifications for your particular LED, let's
say 1.6 volts. Feeding 14 volts would require (guesstimate) about 200
ohms.