How to create a layout cell using skill code

Hi,

Is there any skill command to create a layout cell with library name, cell name and view name as input???

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[Seh Hoong]

On Wednesday, March 19, 2014 1:47:54 PM UTC+8, prav...@sankalpsemi.com wrote:

Hi,



Is there any skill command to create a layout cell with library name, cell name and view name as input???



--

Disclaimer : Privileged and Confidential information is contained in this e

mail and/or attachments and is subject to legal privilege. This e mail is

intended solely for the recipient/s mentioned above. If you are not the

intended recipient or responsible for delivery of the message to the

intended recipient you may not use, copy, distribute or deliver to anyone

this e mail and/or any attachments or any part of its contents or take any

action in reliance on it. In such case, you should destroy this message,

and notify us immediately. All reasonable precautions have been taken to

ensure no viruses are present in this e-mail. Our company is not liable for

any loss arising from unauthorized access to our company's email account by

any third party and/or any loss caused due to the transmission of any

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===
Hi,

You may use this:
deNewCellView( "library_name" "cell_name" "view_name" "maskLayout" nil)

Regards,
Seh Hoong

 

[Andrew Beckett]

On 03/19/14 08:04, Seh Hoong wrote:

On Wednesday, March 19, 2014 1:47:54 PM UTC+8, prav...@sankalpsemi.com wrote:
Hi,



Is there any skill command to create a layout cell with library name, cell name and view name as input???

===
Hi,

You may use this:
deNewCellView( "library_name" "cell_name" "view_name" "maskLayout" nil)

Regards,
Seh Hoong

Or if you don't need a window, you'd use:

cv=dbOpenCellViewByType("libName" "cellName" "viewName" "maskLayout" "a")

Regards,

Andrew.