B
boki
Guest
Dear All,
We calculate the IIR filter coefficient by
h(kt)=(2fc/fs)(sin{r(k)}/r(k))
r(k)=2*pi*fc*[k-(N-1)/2]/fs, k=0,1,2,3,....
pi=3.14159
but, how these equations come from?
Thanks a lot!
Best regards,
Boki.
We calculate the IIR filter coefficient by
h(kt)=(2fc/fs)(sin{r(k)}/r(k))
r(k)=2*pi*fc*[k-(N-1)/2]/fs, k=0,1,2,3,....
pi=3.14159
but, how these equations come from?
Thanks a lot!
Best regards,
Boki.