J
j van c
Guest
Im my thread "transistors" from 22/9/04 Roger explained me how to determine
the C and E with the hfe test after determining the B.
I did a test with a H9012, which is a pnp(diode test).(Black at B measuring
600 mv versus E en C)
B,E and C are marked on the transistor. There's no doubt about this.
The two hfe values are 174 and 41.
So i took the 174-combination. It's quit the opposite.
Am i doiing something wrong.
the C and E with the hfe test after determining the B.
I did a test with a H9012, which is a pnp(diode test).(Black at B measuring
600 mv versus E en C)
B,E and C are marked on the transistor. There's no doubt about this.
The two hfe values are 174 and 41.
So i took the 174-combination. It's quit the opposite.
Am i doiing something wrong.