Guest
I've found this interesting lecture
www.analogzone.com/acqt0704.pdf
but i don't understand open loop gain with resistor series capacitor
as load.In fig. 6.15 opamp's open loop gain is represented: it is
calculated (i think) at node Vout of fig 6.14, so pole is equal to 1/
(Ro+Riso)*Cl. I don't understand how zero is obtained....
Can you help me?
Thanks
www.analogzone.com/acqt0704.pdf
but i don't understand open loop gain with resistor series capacitor
as load.In fig. 6.15 opamp's open loop gain is represented: it is
calculated (i think) at node Vout of fig 6.14, so pole is equal to 1/
(Ro+Riso)*Cl. I don't understand how zero is obtained....
Can you help me?
Thanks