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Hi guys,
I'm a newbie in electronics and I am having a hard time understanding how
this simple circuit works (http://www.mmendes.com/odb_driver.jpg).
The description of the circuit says:
"CLR is active high while AB is active low. These two pulses generate the
timing for ODB."
I am correct to think that the following truth table is correct?
if CLR = 0 and AB = 0 then ODB = ~4.8v
if CLR = 0 and AB = 1 then ODB = ~6.3v
if CLR = 1 and AB = 0 then ODB = ~6.3v
if CLR =1 and AB = 1 then ODB = ~ 12v
Please take a look at the circuit diagram and let me know if I am correct/in
the right way but not quite there/wrong. Again, you can check out the
diagram at http://www.mmendes.com/odb_driver.jpg.
Thanks.
Captain.
PS -> To reply via email, please remove the upper case letters from the
email address. <- "poor man's anti spam"
I'm a newbie in electronics and I am having a hard time understanding how
this simple circuit works (http://www.mmendes.com/odb_driver.jpg).
The description of the circuit says:
"CLR is active high while AB is active low. These two pulses generate the
timing for ODB."
I am correct to think that the following truth table is correct?
if CLR = 0 and AB = 0 then ODB = ~4.8v
if CLR = 0 and AB = 1 then ODB = ~6.3v
if CLR = 1 and AB = 0 then ODB = ~6.3v
if CLR =1 and AB = 1 then ODB = ~ 12v
Please take a look at the circuit diagram and let me know if I am correct/in
the right way but not quite there/wrong. Again, you can check out the
diagram at http://www.mmendes.com/odb_driver.jpg.
Thanks.
Captain.
PS -> To reply via email, please remove the upper case letters from the
email address. <- "poor man's anti spam"