Help! 4 photoswitch

R

Razzel

Guest
I have built several IR/visible switches from schematics found on the web.
My objective is to have an indicator between an unblocked and blocked beam.
I wanted to find one with sufficient voltage separation that a program
could read (via the sound card) the values and determine a boundary
value above or below which would indicate the value meant blocked or
unblocked.
So far my experience indicates that the IR switches have ranges in the
low millivolt area.
The one which shows the most promise is a Radio Shack 276-145
Phototransistor's emitter feeding the base of a PN2484 and the 2484's
emitter goes to ground via an LED and 550 R resistor. Both collectors
are fed with a 9 volt battery.
I just finished the breadboard of "Simple Optical Switch" at Electronics
Lab and the output was again low and variable. Very disappointing.

1) Why does the voltage jump to high levels when unblocked (276-145
version) before dropping below 100?
The digitized values look to be 60-90 after jumping to 190-210 for
2-3 seconds.
Oh and the tests were at 1 second intervals.
2) Why is the voltage unstable when blocked?
The digitized values are 130 for 3-4 seconds then drift all around
(119-125 but occasionally spike) then up to 130 again.
The tests were made under battery power with new 9v (no load) battery.
 
Razzel wrote:
I have built several IR/visible switches from schematics found on the
web. My objective is to have an indicator between an unblocked and
blocked beam.
I wanted to find one with sufficient voltage separation that a program
could read (via the sound card) the values and determine a boundary
value above or below which would indicate the value meant blocked or
unblocked.
Click to expand...
Your sound card input stage has probably a capacitor in it's path to
block the DC component of the signal so you can't really use it as a
digital voltmeter.



Sylvain
 
On Sat, 13 Aug 2005 00:26:28 GMT, Razzel <logicon@zipcon.com> wrote:

I have built several IR/visible switches from schematics found on the web.
My objective is to have an indicator between an unblocked and blocked beam.
I wanted to find one with sufficient voltage separation that a program
could read (via the sound card) the values and determine a boundary
value above or below which would indicate the value meant blocked or
unblocked.
So far my experience indicates that the IR switches have ranges in the
low millivolt area.
The one which shows the most promise is a Radio Shack 276-145
Phototransistor's emitter feeding the base of a PN2484 and the 2484's
emitter goes to ground via an LED and 550 R resistor. Both collectors
are fed with a 9 volt battery.
I just finished the breadboard of "Simple Optical Switch" at Electronics
Lab and the output was again low and variable. Very disappointing.

1) Why does the voltage jump to high levels when unblocked (276-145
version) before dropping below 100?
The digitized values look to be 60-90 after jumping to 190-210 for
2-3 seconds.
Oh and the tests were at 1 second intervals.
2) Why is the voltage unstable when blocked?
The digitized values are 130 for 3-4 seconds then drift all around
(119-125 but occasionally spike) then up to 130 again.
The tests were made under battery power with new 9v (no load) battery.
Click to expand...
---
You're having problems because you don't have the thing wired
properly and also, perhaps, because you don't have the
phototransistor shielded from ambient light.

It should be wired like this:


+9V>--+-----------+--------+
| | |
| [10K] |
| | E
| +-[10K]-B 2N4403
[390] | C
| C |A
[IRLED] --> | Q1 |
| E [LED]
| | |
| GND [390]
| | |
GND>--+-----------+--------+

Where Q1 is your phototransistor.

The 390 ohm resistors will give you about 20mA of current in both
LEDs, and the two 10k resistors will keep the 2N4403 cut off when
the IRLED is off. When the IRLED is on, it'll pull the 10k
resistors down to ground, almost, and turn on the 2N4403 and the
LED.







--
John Fields
Professional Circuit Designer
 
I have built several IR/visible switches from schematics found on the
web. My objective is to have an indicator between an unblocked and
blocked beam.
I wanted to find one with sufficient voltage separation that a program
could read (via the sound card) the values and determine a boundary
value above or below which would indicate the value meant blocked or
unblocked.
So far my experience indicates that the IR switches have ranges in the
low millivolt area.
The one which shows the most promise is a Radio Shack 276-145
Phototransistor's emitter feeding the base of a PN2484 and the 2484's
emitter goes to ground via an LED and 550 R resistor. Both collectors
are fed with a 9 volt battery.
I just finished the breadboard of "Simple Optical Switch" at Electronics
Lab and the output was again low and variable. Very disappointing.

1) Why does the voltage jump to high levels when unblocked (276-145
version) before dropping below 100?
The digitized values look to be 60-90 after jumping to 190-210 for
2-3 seconds.
Oh and the tests were at 1 second intervals.
2) Why is the voltage unstable when blocked?
The digitized values are 130 for 3-4 seconds then drift all around
(119-125 but occasionally spike) then up to 130 again.
The tests were made under battery power with new 9v (no load) battery.
Click to expand...
As pointed out in another post, the sound card will only respond to a
voltage that varies with time, it will not response to a DC voltage. You
can couple your phototransistor to a 555 so that when unblocked the 555
oscillates at an audio frequency like 1KHz, and when blocked the 555
stops oscillation. Something like this:

View in a fixed-width font such as Courier.

..
.. +----------------------------------->
.. |
.. | 9V BATT TO SOUND CARD
.. | ------------
.. | | - |[--+--------->
.. | | | |
.. | | + |] ----+
.. | ------------ | |
.. | 0.1U | |
.. +--||---+-----------------+ |
.. | | |
.. | | |
.. 1K | 1K | 22U + |
.. +---/\/\--+-/\/\--+--------||----------+
.. | | |
.. | ~ | 0.22U | 1K
.. +---------+--|>|--+--------||----------+---/\/\--+
.. | LED | | |
.. | | ----- -LM555 | |
.. 0.01U | | | \_/ | | PTR |
.. +--||-----|-------+--| GND V+ |--+ ------|--
.. | | | | | | c |
.. | 220/ 47K/ | | | |/ |
.. +---------\-------\--| TRIG DIS | |~~~ | |
.. | / / | | | |\ |
.. | | | | | | e |
.. | +-------|--| OUT THRESH |--+ ------|--
.. | | | | | | |
.. | 68K / | | | | |
.. | \ +--| RST CON | | |
.. | / | -------------- | |
.. | | | | |
.. +---------+-------|--------------------+ |
.. | |
.. +------------------------------+
..
..
..
 
Fred Bloggs wrote:
I have built several IR/visible switches from schematics found on the
web. My objective is to have an indicator between an unblocked and
blocked beam.
I wanted to find one with sufficient voltage separation that a program
could read (via the sound card) the values and determine a boundary
value above or below which would indicate the value meant blocked or
unblocked.
So far my experience indicates that the IR switches have ranges in the
low millivolt area.
The one which shows the most promise is a Radio Shack 276-145
Phototransistor's emitter feeding the base of a PN2484 and the 2484's
emitter goes to ground via an LED and 550 R resistor. Both collectors
are fed with a 9 volt battery.
I just finished the breadboard of "Simple Optical Switch" at
Electronics Lab and the output was again low and variable. Very
disappointing.

1) Why does the voltage jump to high levels when unblocked (276-145
version) before dropping below 100?
The digitized values look to be 60-90 after jumping to 190-210 for
2-3 seconds.
Oh and the tests were at 1 second intervals.
2) Why is the voltage unstable when blocked?
The digitized values are 130 for 3-4 seconds then drift all around
(119-125 but occasionally spike) then up to 130 again.
The tests were made under battery power with new 9v (no load) battery.


As pointed out in another post, the sound card will only respond to a
voltage that varies with time, it will not response to a DC voltage. You
can couple your phototransistor to a 555 so that when unblocked the 555
oscillates at an audio frequency like 1KHz, and when blocked the 555
stops oscillation. Something like this:

View in a fixed-width font such as Courier.

.
. +-----------------------------------
. |
. | 9V BATT TO SOUND CARD
. | ------------
. | | - |[--+---------
. | | | |
. | | + |] ----+
. | ------------ | |
. | 0.1U | |
. +--||---+-----------------+ |
. | | |
. | | |
. 1K | 1K | 22U + |
. +---/\/\--+-/\/\--+--------||----------+
. | | |
. | ~ | 0.22U | 1K
. +---------+--|>|--+--------||----------+---/\/\--+
. | LED | | |
. | | ----- -LM555 | |
. 0.01U | | | \_/ | | PTR |
. +--||-----|-------+--| GND V+ |--+ ------|--
. | | | | | | c |
. | 220/ 47K/ | | | |/ |
. +---------\-------\--| TRIG DIS | |~~~ | |
. | / / | | | |\ |
. | | | | | | e |
. | +-------|--| OUT THRESH |--+ ------|--
. | | | | | | |
. | 68K / | | | | |
. | \ +--| RST CON | | |
. | / | -------------- | |
. | | | | |
. +---------+-------|--------------------+ |
. | |
. +------------------------------+
.
.
.
Click to expand...
I suppose a little hysteresis would not hurt:

View in a fixed-width font such as Courier.

..
..
.. +----------------------------------->
.. |
.. | TO SOUND CARD
.. |
.. | +---------->
.. | |
.. | 9V BATT |
.. | ------------ |
.. | | - |[--+
.. | | | |
.. | | + |] ----+
.. | ------------ | |
.. | | |
.. | | |
.. | | |
.. | 0.1U | |
.. +--||---+-----------------+ |
.. | | |
.. | | |
.. 1K | 1K | 22U + |
.. +---/\/\--+-/\/\--+--------||----------+
.. | | |
.. | ~ | 0.22U | 1K
.. +---------+--|>|--+--------||----------+--/\/\-----------+
.. | LED | | |
.. | | ----- -LM555 | |
.. 0.01U | | | \_/ | | PTR |
.. +--||-----|-------+--| GND V+ |--+ ------|--
.. | | | | | | c |
.. | 220/ 47K/ | | | |/ |
.. +---------\-------\--| TRIG DIS | |~~~ | |
.. | / / | | | |\ |
.. | | | | | | e |
.. | +-------|--| OUT THRESH |--+ ------|--
.. | | | | | | |
.. | 68K | 3.3M | | | | |
.. +----/\/\-+-/\/\--+--| RST CON | | |
.. | | -------------- | |
.. | | | |
.. +-----------------|--------------------+ |
.. | |
.. +--------------------------------------+
..
..
..
 
Fred Bloggs wrote:
Fred Bloggs wrote:




I have built several IR/visible switches from schematics found on the
web. My objective is to have an indicator between an unblocked and
blocked beam.
I wanted to find one with sufficient voltage separation that a
program could read (via the sound card) the values and determine a
boundary value above or below which would indicate the value meant
blocked or unblocked.
So far my experience indicates that the IR switches have ranges in
the low millivolt area.
The one which shows the most promise is a Radio Shack 276-145
Phototransistor's emitter feeding the base of a PN2484 and the 2484's
emitter goes to ground via an LED and 550 R resistor. Both
collectors are fed with a 9 volt battery.
I just finished the breadboard of "Simple Optical Switch" at
Electronics Lab and the output was again low and variable. Very
disappointing.

1) Why does the voltage jump to high levels when unblocked (276-145
version) before dropping below 100?
The digitized values look to be 60-90 after jumping to 190-210
for 2-3 seconds.
Oh and the tests were at 1 second intervals.
2) Why is the voltage unstable when blocked?
The digitized values are 130 for 3-4 seconds then drift all
around (119-125 but occasionally spike) then up to 130 again.
The tests were made under battery power with new 9v (no load) battery.



As pointed out in another post, the sound card will only respond to a
voltage that varies with time, it will not response to a DC voltage.
You can couple your phototransistor to a 555 so that when unblocked
the 555 oscillates at an audio frequency like 1KHz, and when blocked
the 555 stops oscillation. Something like this:

View in a fixed-width font such as Courier.

.
. +-----------------------------------
. |
. | 9V BATT TO SOUND CARD
. | ------------
. | | - |[--+---------
. | | | |
. | | + |] ----+
. | ------------ | |
. | 0.1U | |
. +--||---+-----------------+ |
. | | |
. | | |
. 1K | 1K | 22U + |
. +---/\/\--+-/\/\--+--------||----------+
. | | |
. | ~ | 0.22U | 1K
. +---------+--|>|--+--------||----------+---/\/\--+
. | LED | | |
. | | ----- -LM555 | |
. 0.01U | | | \_/ | | PTR |
. +--||-----|-------+--| GND V+ |--+ ------|--
. | | | | | | c |
. | 220/ 47K/ | | | |/ |
. +---------\-------\--| TRIG DIS | |~~~ | |
. | / / | | | |\ |
. | | | | | | e |
. | +-------|--| OUT THRESH |--+ ------|--
. | | | | | | |
. | 68K / | | | | |
. | \ +--| RST CON | | |
. | / | -------------- | |
. | | | | |
. +---------+-------|--------------------+ |
. | |
. +------------------------------+
.
.
.


I suppose a little hysteresis would not hurt:

View in a fixed-width font such as Courier.

.
.
. +-----------------------------------
. |
. | TO SOUND CARD
. |
. | +----------
. | |
. | 9V BATT |
. | ------------ |
. | | - |[--+
. | | | |
. | | + |] ----+
. | ------------ | |
. | | |
. | | |
. | | |
. | 0.1U | |
. +--||---+-----------------+ |
. | | |
. | | |
. 1K | 1K | 22U + |
. +---/\/\--+-/\/\--+--------||----------+
. | | |
. | ~ | 0.22U | 1K
. +---------+--|>|--+--------||----------+--/\/\-----------+
. | LED | | |
. | | ----- -LM555 | |
. 0.01U | | | \_/ | | PTR |
. +--||-----|-------+--| GND V+ |--+ ------|--
. | | | | | | c |
. | 220/ 47K/ | | | |/ |
. +---------\-------\--| TRIG DIS | |~~~ | |
. | / / | | | |\ |
. | | | | | | e |
. | +-------|--| OUT THRESH |--+ ------|--
. | | | | | | |
. | 68K | 3.3M | | | | |
. +----/\/\-+-/\/\--+--| RST CON | | |
. | | -------------- | |
. | | | |
. +-----------------|--------------------+ |
. | |
. +--------------------------------------+
.
.
.
Click to expand...
That works for the CMOS 555 , but the RST current required for the
bipolar version will require doing something more like this:
View in a fixed-width font such as Courier.

..
..
.. +----------------------------------->
.. |
.. | TO SOUND CARD
.. |
.. | +---------->
.. | |
.. | 9V BATT | +------------+
.. | ------------ | | PTR |
.. | | - |[--+ | ------|--
.. | | | | | | c |
.. | | + |] ----+ | | |/ |
.. | ------------ | | | |~~~ | |
.. | | | | | |\ |
.. | | | | | e |
.. | | | | ------|--
.. | 0.1U | | | |
.. +--||---+-----------------+--|--------------------+
.. | | | |
.. | | | |
.. 1K | 1K | 22U + | 100K |
.. +---/\/\--+-/\/\--+--------||----------+-/\/\--+---------+
.. | | | |
.. | ~ | 0.22U | 47K |
.. +---------+--|>|--+--------||----------+-/\/\--+-----+ |
.. | LED | | | | |
.. | | ----- -LM555 | | c |
.. 0.01U | | | \_/ | | | \| |
.. +--||-----|-------+--| GND V+ |--+ | PN2484|-+
.. | | | | | /|
.. | 220/ | | | e
.. +---------\----------| TRIG DIS |----------|-----+
.. | / | | |
.. | 68K | | | |
.. +--/\/\---+----------| OUT THRESH |--+ |
.. | | | | |
.. | | | | |
.. | +--| RST CON | | |
.. | | -------------- | |
.. | | | |
.. +-----------------|--------------------+ |
.. | |
.. +----------------------------+
..
 
On Sat, 13 Aug 2005 07:15:14 -0500, John Fields
<jfields@austininstruments.com> wrote:


You're having problems because you don't have the thing wired
properly and also, perhaps, because you don't have the
phototransistor shielded from ambient light.

It should be wired like this:


+9V>--+-----------+--------+
| | |
| [10K] |
| | E
| +-[10K]-B 2N4403
[390] | C
| C |A
[IRLED] --> | Q1 |
| E [LED]
| | |
| GND [390]
| | |
GND>--+-----------+--------+

Where Q1 is your phototransistor.

The 390 ohm resistors will give you about 20mA of current in both
LEDs, and the two 10k resistors will keep the 2N4403 cut off when
the IRLED is off. When the IRLED is on, it'll pull the 10k
resistors down to ground, almost, and turn on the 2N4403 and the
LED.
Click to expand...
---
Or, for an audio output to a sound card:


9V
7555 |
+-------+ 10K[POT]<-[0.1]-->TO SOUND CARD
+--|TH R|O---Vcc |
| |__ | C
+-O|TR OUT|--+--[390]--[IRLED>]~~~B 276-145
| +-------+ | E
+----[6k8]----+ |
| GND
[0.1]
|
GND

When the beam isn't broken, there'll be about a 1kHz signal on the
output to the sound card. If the sound card's input is internally
capacitively coupled to the outside world, the 0.1ľF cap on the arm
of the pot can be omitted.


--
John Fields
Professional Circuit Designer
 
John Fields wrote:
On Sat, 13 Aug 2005 07:15:14 -0500, John Fields
jfields@austininstruments.com> wrote:



You're having problems because you don't have the thing wired
properly and also, perhaps, because you don't have the
phototransistor shielded from ambient light.

It should be wired like this:


+9V>--+-----------+--------+
| | |
| [10K] |
| | E
| +-[10K]-B 2N4403
[390] | C
| C |A
[IRLED] --> | Q1 |
| E [LED]
| | |
| GND [390]
| | |
GND>--+-----------+--------+

Where Q1 is your phototransistor.

The 390 ohm resistors will give you about 20mA of current in both
LEDs, and the two 10k resistors will keep the 2N4403 cut off when
the IRLED is off. When the IRLED is on, it'll pull the 10k
resistors down to ground, almost, and turn on the 2N4403 and the
LED.


---
Or, for an audio output to a sound card:


9V
7555 |
+-------+ 10K[POT]<-[0.1]-->TO SOUND CARD
+--|TH R|O---Vcc |
| |__ | C
+-O|TR OUT|--+--[390]--[IRLED>]~~~B 276-145
| +-------+ | E
+----[6k8]----+ |
| GND
[0.1]
|
GND

When the beam isn't broken, there'll be about a 1kHz signal on the
output to the sound card. If the sound card's input is internally
capacitively coupled to the outside world, the 0.1ľF cap on the arm
of the pot can be omitted.
Click to expand...
From the original description of a "diode" in the emitter and checking
the sound card every second, it sounds like he was using an IR latched
switch like so:
View in a fixed-width font such as Courier.

..
.. Vbatt
.. |
.. |
.. +-------+----+
.. | | |
.. c | |
.. +--+ _ |/ | o|
.. | | /| ~~~ | | +
.. |r | / |\ | o|
.. |e | / e | |
.. |f | / | | |
.. |l | / +-------|----+
.. |e | / | |
.. |c | / [Rb] |
.. |t | / | c
.. |o | _ | |/
.. |r ||\ +-----|
.. | | \ |\
.. | | \ e
.. | | \ |
.. | | \ |
.. +--+ \ +-[Re]--+
.. \ |
.. \ ---
.. ~~~ \ /
.. ---
.. |
.. |
.. gnd
..
..
..
 
I read in sci.electronics.design that Fred Bloggs <nospam@nospam.com>
wrote (in <4301DE6E.2070400@nospam.com>) about 'Help! 4 photoswitch', on
Tue, 16 Aug 2005:
From the original description of a "diode" in the emitter and checking
the sound card every second, it sounds like he was using an IR latched
switch like so:
View in a fixed-width font such as Courier.
Click to expand...
Hi, Fred. Another great 'Muriel'!
--
Regards, John Woodgate, OOO - Own Opinions Only.
There are two sides to every question, except
'What is a Moebius strip?'
http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk
 
John Woodgate wrote:
I read in sci.electronics.design that Fred Bloggs <nospam@nospam.com
wrote (in <4301DE6E.2070400@nospam.com>) about 'Help! 4 photoswitch', on
Tue, 16 Aug 2005:

From the original description of a "diode" in the emitter and checking
the sound card every second, it sounds like he was using an IR latched
switch like so:
View in a fixed-width font such as Courier.


Hi, Fred. Another great 'Muriel'!
Click to expand...
Thnx- anyone who likes transistors will like this:

View in a fixed-width font such as Courier.

..
..
..
..
..
..
.. Vbatt
.. |
.. +--------------------------+
.. | |
.. [Re] e
.. | |/
.. +---------[10K]----------| 2N3906
.. | |\
.. | c
.. --- |
.. ~~~ \ / |
.. +--+ --- |
.. | | | |
.. |r | +--------------------+ | 7555 OSC
.. |e | / | | +-------+
.. |f | / | | | |
.. |l | / +-[47K]-+------------------+---|RST |--> to
.. |e | / | | | | | | souncard
.. |c | / | e | | | |
.. |t ||/ | |/ | | | |
.. |o | - +-----|2N3906 | [47K] | |
.. |r | \ | |\ | | | |
.. | | \ | c | | | |
.. | | \ | | | | +-------+
.. | | \ [47K] [4.7K] | | |
.. | | \| | | | +-------+
.. +--+ - | | +--|<|---+ |
.. | | | 1N914 | gnd
.. c | | |
.. |/ | o| |
.. ~~~ | | |- |
.. |\ | o| |
.. e | | c
.. | | | |/
.. | +---+------|2N4401
.. | | |\
.. | [10K] e
.. | | |
.. +-------+------------+
.. |
.. gnd
..
 
On Tue, 16 Aug 2005 12:39:26 GMT, Fred Bloggs <nospam@nospam.com>
wrote:

John Fields wrote:
On Sat, 13 Aug 2005 07:15:14 -0500, John Fields
jfields@austininstruments.com> wrote:



You're having problems because you don't have the thing wired
properly and also, perhaps, because you don't have the
phototransistor shielded from ambient light.

It should be wired like this:


+9V>--+-----------+--------+
| | |
| [10K] |
| | E
| +-[10K]-B 2N4403
[390] | C
| C |A
[IRLED] --> | Q1 |
| E [LED]
| | |
| GND [390]
| | |
GND>--+-----------+--------+

Where Q1 is your phototransistor.

The 390 ohm resistors will give you about 20mA of current in both
LEDs, and the two 10k resistors will keep the 2N4403 cut off when
the IRLED is off. When the IRLED is on, it'll pull the 10k
resistors down to ground, almost, and turn on the 2N4403 and the
LED.


---
Or, for an audio output to a sound card:


9V
7555 |
+-------+ 10K[POT]<-[0.1]-->TO SOUND CARD
+--|TH R|O---Vcc |
| |__ | C
+-O|TR OUT|--+--[390]--[IRLED>]~~~B 276-145
| +-------+ | E
+----[6k8]----+ |
| GND
[0.1]
|
GND

When the beam isn't broken, there'll be about a 1kHz signal on the
output to the sound card. If the sound card's input is internally
capacitively coupled to the outside world, the 0.1ľF cap on the arm
of the pot can be omitted.



From the original description of a "diode" in the emitter and checking
the sound card every second, it sounds like he was using an IR latched
switch like so:
View in a fixed-width font such as Courier.

.
. Vbatt
. |
. |
. +-------+----+
. | | |
. c | |
. +--+ _ |/ | o|
. | | /| ~~~ | | +
. |r | / |\ | o|
. |e | / e | |
. |f | / | | |
. |l | / +-------|----+
. |e | / | |
. |c | / [Rb] |
. |t | / | c
. |o | _ | |/
. |r ||\ +-----|
. | | \ |\
. | | \ e
. | | \ |
. | | \ |
. +--+ \ +-[Re]--+
. \ |
. \ ---
. ~~~ \ /
. ---
. |
. |
. gnd
.
.
.
Click to expand...
---
Actually, he was quite specific that the "diode" was an LED, in that
he wrote ..."the 2484's emitter goes to ground via an LED and 550 R
resistor." , so my take on it was that the LED in the emitter was
just a visual indicator, not the IR source, which would have been
called "the" LED.

Anyway, after reading his first paragraph about using "voltage
separation" and a sound card to do the detection, and following his
link to:

http://www.electronics-lab.com/projects/misc/017/

I decided he basically didn't know what he was doing, so I provided
him with a circuit which would give him a large voltage differential
between the beam's blocked and unblocked states and then, later, a
circuit which would give him an AC output he could run into his
sound card if he wanted to do the detection that way, by checking
for the presence of AC every second or so...

--
John Fields
Professional Circuit Designer
 
John Fields wrote:
On Tue, 16 Aug 2005 12:39:26 GMT, Fred Bloggs <nospam@nospam.com
wrote:



John Fields wrote:

On Sat, 13 Aug 2005 07:15:14 -0500, John Fields
jfields@austininstruments.com> wrote:




You're having problems because you don't have the thing wired
properly and also, perhaps, because you don't have the
phototransistor shielded from ambient light.

It should be wired like this:


+9V>--+-----------+--------+
| | |
| [10K] |
| | E
| +-[10K]-B 2N4403
[390] | C
| C |A
[IRLED] --> | Q1 |
| E [LED]
| | |
| GND [390]
| | |
GND>--+-----------+--------+

Where Q1 is your phototransistor.

The 390 ohm resistors will give you about 20mA of current in both
LEDs, and the two 10k resistors will keep the 2N4403 cut off when
the IRLED is off. When the IRLED is on, it'll pull the 10k
resistors down to ground, almost, and turn on the 2N4403 and the
LED.


---
Or, for an audio output to a sound card:


9V
7555 |
+-------+ 10K[POT]<-[0.1]-->TO SOUND CARD
+--|TH R|O---Vcc |
| |__ | C
+-O|TR OUT|--+--[390]--[IRLED>]~~~B 276-145
| +-------+ | E
+----[6k8]----+ |
| GND
[0.1]
|
GND

When the beam isn't broken, there'll be about a 1kHz signal on the
output to the sound card. If the sound card's input is internally
capacitively coupled to the outside world, the 0.1ľF cap on the arm
of the pot can be omitted.



From the original description of a "diode" in the emitter and checking
the sound card every second, it sounds like he was using an IR latched
switch like so:
View in a fixed-width font such as Courier.

.
. Vbatt
. |
. |
. +-------+----+
. | | |
. c | |
. +--+ _ |/ | o|
. | | /| ~~~ | | +
. |r | / |\ | o|
. |e | / e | |
. |f | / | | |
. |l | / +-------|----+
. |e | / | |
. |c | / [Rb] |
. |t | / | c
. |o | _ | |/
. |r ||\ +-----|
. | | \ |\
. | | \ e
. | | \ |
. | | \ |
. +--+ \ +-[Re]--+
. \ |
. \ ---
. ~~~ \ /
. ---
. |
. |
. gnd
.
.
.


---
Actually, he was quite specific that the "diode" was an LED, in that
he wrote ..."the 2484's emitter goes to ground via an LED and 550 R
resistor." , so my take on it was that the LED in the emitter was
just a visual indicator, not the IR source, which would have been
called "the" LED.

Anyway, after reading his first paragraph about using "voltage
separation" and a sound card to do the detection, and following his
link to:

http://www.electronics-lab.com/projects/misc/017/

I decided he basically didn't know what he was doing, so I provided
him with a circuit which would give him a large voltage differential
between the beam's blocked and unblocked states and then, later, a
circuit which would give him an AC output he could run into his
sound card if he wanted to do the detection that way, by checking
for the presence of AC every second or so...
Click to expand...
I know- well the yo-yo's keep calling an IR LED "the" LED.
 
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