four Lead Acid batteries

J

Jif

Guest
hi

i have 4 batteries (identical) 6v / 4.5AH

if i connect them (parallel or series)
do i get the total volts and ampere (6V x 4 =24V) or (4.5Amp x 4=18Amp)


btw: it is writen 4.5AH for ampers, what is the AH stand for and means

deep thanks

jif
 
"Jif" <987JIF@anon.lcs.mit.edu> wrote in message
news:EXCLUSTER1SINrSxbRV0001d310@EXCH2KCL.nesma.net.sa...
hi

i have 4 batteries (identical) 6v / 4.5AH

if i connect them ( llel or series)
do i get the total volts and ampere (6V x 4 =24V) or (4.5Amp x 4=18Amp)


btw: it is writen 4.5AH for ampers, what is the AH stand for and means

deep thanks

jif
AH stands for Amp Hours, so you could draw 4.5 Amps for 1 hour or 9 Amps for
half an hour, etc.

Harry





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In article <EXCLUSTER1SINrSxbRV0001d310@EXCH2KCL.nesma.net.sa>,
987JIF@anon.lcs.mit.edu says...
hi

i have 4 batteries (identical) 6v / 4.5AH

if i connect them (parallel or series)
do i get the total volts and ampere (6V x 4 =24V) or (4.5Amp x 4=18Amp)


btw: it is writen 4.5AH for ampers, what is the AH stand for and means
AH == Ampere*Hours Thus, a 4.5AH battery will supply 4.5A for one hour
or 1A for 4.5H, or there abouts (the discharge curve isn't linear).

--
Keith
 
"Jif" <987JIF@anon.lcs.mit.edu> wrote in message
news:EXCLUSTER1SINrSxbRV0001d310@EXCH2KCL.nesma.net.sa...
i have 4 batteries (identical) 6v / 4.5AH

if i connect them (parallel or series)
do i get the total volts and ampere (6V x 4 =24V) or (4.5Amp x 4=18Amp)


btw: it is writen 4.5AH for ampers, what is the AH stand for and means
AH is amp-hours: it is a measure of how much energy the battery stores. A
4.5AH battery will supply 4.5 amperes for one hour before discharging; or 1A
for 4.5hrs; or 3A for 1.5hrs; you get the picture. It's an approximation;
often the amount of current you draw affects the battery's efficiency. So
it really means "4.5AH at the optimal discharge rate, and less otherwise."

The actual amount of current the battery can provide is determined by its
internal impedance. Could be 100A, could be 0.1A, no way to know from your
description.

If you put batteries in series, the voltage adds, but the current capability
(that is, the actual amount of current the battery can provide) is
unchanged.

If you put batteries in parallel, the voltage is unchanged, but the current
capability adds, at least within the limits of how much current the wiring
and the connectors can handle.

Regardless of how they're hooked up, the energy capacity (AH) of each
individual battery is unchanged. So, if you hook four in parallel, you've
got a 6v 18AH battery.
 
"Jif" <987JIF@anon.lcs.mit.edu> wrote in message
news:0HPG00IKTIZVQ4@fe-ims1.awalnet.net.sa...
Many thanks for all the help and just one final post

Let say I have connected these batteries in parallel and at the end can I
install
current regulator so I can adjust the current output. Any part number or
name.

The total volt will be 6V so can I use volt regulator LM350T (1.3V to 30V)
to
adjust volt as well to 3V or 5V
is this diagram correct

[ Bat1] ...... [ Bat n] === Volt reg ====Amp Reg == Ammeter ====Voltmeter


Many thanks in advance

Ohm's Law says voltage equals current times resistance. For a given load
resistance, you can regulate voltage or current, not both!

Can you tell us what exactly it is you're trying to do? These abstract
questions are not really helping you understand what's going on, I fear.
 
Many thanks for all the help and just one final post

Let say I have connected these batteries in parallel and at the end can I install
current regulator so I can adjust the current output. Any part number or name.

The total volt will be 6V so can I use volt regulator LM350T (1.3V to 30V) to
adjust volt as well to 3V or 5V
is this diagram correct

[ Bat1] ...... [ Bat n] === Volt reg ====Amp Reg == Ammeter ====Voltmeter


Many thanks in advance

jif

AH is amp-hours: it is a measure of how much energy the battery stores. A
4.5AH battery will supply 4.5 amperes for one hour before discharging; or 1A
for 4.5hrs; or 3A for 1.5hrs; you get the picture. It's an approximation;
often the amount of current you draw affects the battery's efficiency. So
it really means "4.5AH at the optimal discharge rate, and less otherwise."

The actual amount of current the battery can provide is determined by its
internal impedance. Could be 100A, could be 0.1A, no way to know from your
description.

If you put batteries in series, the voltage adds, but the current capability
(that is, the actual amount of current the battery can provide) is
unchanged.

If you put batteries in parallel, the voltage is unchanged, but the current
capability adds, at least within the limits of how much current the wiring
and the connectors can handle.

Regardless of how they're hooked up, the energy capacity (AH) of each
individual battery is unchanged. So, if you hook four in parallel, you've
got a 6v 18AH battery.



i have 4 batteries (identical) 6v / 4.5AH

if i connect them (parallel or series)
do i get the total volts and ampere (6V x 4 =24V) or (4.5Amp x 4=18Amp)


btw: it is writen 4.5AH for ampers, what is the AH stand for and means
 
On Fri, 5 Dec 2003 21:46:44 +3, "Jif" <987JIF@anon.lcs.mit.edu> wrote:

hi

i have 4 batteries (identical) 6v / 4.5AH

if i connect them (parallel or series)
There is a difference.

--

Boris Mohar
 
Jif wrote:
Many thanks for all the help and just one final post

Let say I have connected these batteries in parallel and at the end can I install
current regulator so I can adjust the current output. Any part number or name.

The total volt will be 6V so can I use volt regulator LM350T (1.3V to 30V) to
adjust volt as well to 3V or 5V
is this diagram correct

[ Bat1] ...... [ Bat n] === Volt reg ====Amp Reg == Ammeter ====Voltmeter

Many thanks in advance

jif
A couple of points. First, the voltage regulator needs some
"overhead" to operate. The best you can get out of it with 6
volts in is a bit less than 5 volts out.

Next, you can regulate either the current through, or voltage
across the load (the device connected to the supply), but you
can't regulate both simultaneously. I think your intention is
really to use the voltage regulator to create a fixed 5 volt
power supply and than to add a current regulator so that you
can control current through the load. You can do that, but
understand that the voltage across the load will not be
regulated - it will change as the current changes.
 

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