Figuring out how to configure CD4060B clock

I have been using and tinkering with a 4060 IC as part of learning various electronics. And I have one and it feels like I am missing some understanding on how things really work.

Using this IC: http://www.digikey.com/product-detail/en/CD4060BM96/296-31513-1-ND/3505795

I cannot figure out how to set the resistor and capacitor on pins 9,10,11 and get a true understanding of what is going on.

In the data sheet it has

ÎŚO: pin 9
ÎŚ(with overbar)O: pin 10
ÎŚI: pin 11

I'm looking to get clarification on how these pins really work. How do I set the values to get the timing I am looking for on the Q outputs?

I have an example with

|---100N--------pin 9
|
|---133k--------pin 10
|
|---1M6---------pin 11

Thats a 100N cap on pin 9, 133k resistor on pin 10 and 1M6 resistor on pin 11 all connected to each other.

And was told this will give the chip a 34Hz operation and 1/34Hz * 2^13 seconds for the pulse rate on Q14 with this configuration. Approx 4 minutes on Q14

First question: How do you actually calculate the Hz operation from those component values on pins 9,10,11?

And is the formula correct for figuring out the pulse rate of a Q output?

How does one figure out how to change the clock Hz with the cap and resistor values? As I cannot seem to find this data in the datasheet.

The ÎŚO abbreviation was this intended to be called (Phi output?) and likewise for ÎŚI (Phi Input?). Any background info why the Phi symbols were used? And not sure what to call the Phi with the overbar.

I have been spending some significant time going over this and feel like I am missing information in order to be able to really understand how this chip works. Even dug through a pile of 4060 descriptions but have been unable to figure out the above. I realize there may be other 4060 IC's but I have this on hand and in use so would like to understand this IC to better my understanding of the other parts of the existing project using this IC.

Assistance would be amazing.

 

[Don Kuenz]

eric@bauld.com wrote:

I have been using and tinkering with a 4060 IC as part of learning various
electronics. And I have one and it feels like I am missing some
understanding on how things really work.

Using this IC: http://www.digikey.com/product-detail/en/CD4060BM96/296-31513-1-ND/3505795

I cannot figure out how to set the resistor and capacitor on pins 9,10,11
and get a true understanding of what is going on.

In the data sheet it has

?O: pin 9
?(with overbar)O: pin 10
?I: pin 11

I'm looking to get clarification on how these pins really work. How do
I set the values to get the timing I am looking for on the Q outputs?

I have an example with

|---100N--------pin 9
|
|---133k--------pin 10
|
|---1M6---------pin 11

Thats a 100N cap on pin 9, 133k resistor on pin 10 and 1M6 resistor on
pin 11 all connected to each other.

And was told this will give the chip a 34Hz operation and
1/34Hz * 2^13 seconds for the pulse rate on Q14 with this
configuration. Approx 4 minutes on Q14

First question: How do you actually calculate the Hz operation from
those component values on pins 9,10,11?

Figure 12 on page 3-160 of the Datasheets link more or less shows:

Cx
+---------+------||------+
| | |

|
Rs > Rx |
|

| | |
11 10 9

NOTE:
Rs is 2Rx to 10Rx
T = 2.2 RxCx

--

( \_/ )
(='-'=) Don Kuenz
(")_(")

 

[Don Kuenz]

John Fields <jfields@austininstruments.com> wrote:

On Wed, 10 Dec 2014 03:27:53 +0000 (UTC), Don Kuenz
garbage@crcomp.net> wrote:
Figure 12 on page 3-160 of the Datasheets link more or less shows:

Cx
+---------+------||------+
| | |
|
Rs > Rx |
|
| | |
11 10 9

NOTE:
Rs is 2Rx to 10Rx
T = 2.2 RxCx

---
That would put Rx in parallel with Rs, which would yield an error.

Did you mistake pin 11 at the bottom of Rs and pin 10 at the bottom of
Rx in my schematic for ground? That's not ground. Rx is NOT in
parallel with Rs.

--

( \_/ )
(='-'=) Don Kuenz
(")_(")

 

[John Fields]

On Wed, 10 Dec 2014 03:27:53 +0000 (UTC), Don Kuenz
<garbage@crcomp.net> wrote:

eric@bauld.com wrote:
I have been using and tinkering with a 4060 IC as part of learning various
electronics. And I have one and it feels like I am missing some
understanding on how things really work.

Using this IC: http://www.digikey.com/product-detail/en/CD4060BM96/296-31513-1-ND/3505795

I cannot figure out how to set the resistor and capacitor on pins 9,10,11
and get a true understanding of what is going on.

In the data sheet it has

?O: pin 9
?(with overbar)O: pin 10
?I: pin 11

I'm looking to get clarification on how these pins really work. How do
I set the values to get the timing I am looking for on the Q outputs?

I have an example with

|---100N--------pin 9
|
|---133k--------pin 10
|
|---1M6---------pin 11

Thats a 100N cap on pin 9, 133k resistor on pin 10 and 1M6 resistor on
pin 11 all connected to each other.

And was told this will give the chip a 34Hz operation and
1/34Hz * 2^13 seconds for the pulse rate on Q14 with this
configuration. Approx 4 minutes on Q14

First question: How do you actually calculate the Hz operation from
those component values on pins 9,10,11?

Figure 12 on page 3-160 of the Datasheets link more or less shows:

Cx
+---------+------||------+
| | |
|
Rs > Rx |
|
| | |
11 10 9

NOTE:
Rs is 2Rx to 10Rx
T = 2.2 RxCx

---
That would put Rx in parallel with Rs, which would yield an error.

On page 3-160, the data sheet really shows:

https://www.dropbox.com/s/juzitv3fdo7dc47/cd4060b.pdf?dl=0

1
so f = -----------
2.2 Rx Cx

 

On Wednesday, December 10, 2014 12:30:37 PM UTC-8, Don Kuenz wrote:

John Fields <jfields@austininstruments.com> wrote:
On Wed, 10 Dec 2014 03:27:53 +0000 (UTC), Don Kuenz
garbage@crcomp.net> wrote:
Figure 12 on page 3-160 of the Datasheets link more or less shows:

Cx
+---------+------||------+
| | |
|
Rs > Rx |
|
| | |
11 10 9

NOTE:
Rs is 2Rx to 10Rx
T = 2.2 RxCx

---
That would put Rx in parallel with Rs, which would yield an error.


Did you mistake pin 11 at the bottom of Rs and pin 10 at the bottom of
Rx in my schematic for ground? That's not ground. Rx is NOT in
parallel with Rs.

--

( \_/ )
(='-'=) Don Kuenz
(")_(")

Thanks, I had missed that function in Fig 12. Or I really was not sure that was the correct one to use.

After sitting down and crunching numbers I feel I have a much better idea of what is going on.

At first using T= 2.2 Rx Cx
I did not realize Rx is in Ohms, Cx is in Farads and T is seconds. Once I figured that out I knew the timing on the parts I have
T = 0.02926 seconds T = 29.26 milliseconds

And then figured the Hz = 1/T or 1000/ms
So Hz = 1/0.02926
= 34.17Hz So pretty much 34Hz

And then did a chart from there using Time Q output = 2^(Q# - 1) * (1/34) gives me the time in seconds that pin will change state at.

I need that push in the right direction and this is making more sense now.

Have some follow up questions.
Rs=1M6, Rx = 133k
The Rs Value I have is actually 12Rx data sheet says 2Rx to 10Rx would anyone know what effect that could have on the circuit?