I
Ian Macmillan
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Have a look at my blog - there might be something of interest there:
merlins-mutterings.blogspot.com
All the best
Ian Macmillan
merlins-mutterings.blogspot.com
All the best
Ian Macmillan
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** Oh dear - your very first item has a serious math error.Have a look at my blog - there might be something of interest there:
merlins-mutterings.blogspot.com
Silly me, confusing symbols mainly. But I did point out that the mystery"Ian Macmillan"
Have a look at my blog - there might be something of interest there:
merlins-mutterings.blogspot.com
** Oh dear - your very first item has a serious math error.
The formula for charge Q on a capacitor is simply:
Q = CV
The formula for the energy E stored in a capacitor is:
E = 0.5CV*2
In the case where a charged cap is connected in parallel with an uncharged
one of the same rating - the resulting voltage of the combination is
found
by considering the law of " conservation of charge " - that is the CV of
the combination is the SAME as the CV of the first cap.
So, the combination will have exactly half the V across it - seeing as C
has now doubled.
The mystery in the puzzle is explaining what happened to the missing
ENERGY
!!
..... Phil
** Where is that pointed out ?"Phil Allison"
Have a look at my blog - there might be something of interest there:
merlins-mutterings.blogspot.com
** Oh dear - your very first item has a serious math error.
The formula for charge Q on a capacitor is simply:
Q = CV
The formula for the energy E stored in a capacitor is:
E = 0.5CV*2
In the case where a charged cap is connected in parallel with an
uncharged
one of the same rating - the resulting voltage of the combination is
found by considering the law of " conservation of charge " - that is the
CV
of the combination is the SAME as the CV of the first cap.
So, the combination will have exactly half the V across it - seeing as C
has now doubled.
The mystery in the puzzle is explaining what happened to the missing
ENERGY !!
Silly me, confusing symbols mainly. But I did point out that the mystery
energy loss was in the discharge path,
** Fraid it does not have much of one.which was the point of the article.
"Ian Macmillan"
Have a look at my blog - there might be something of interest there:
merlins-mutterings.blogspot.com
** Oh dear - your very first item has a serious math error.
The formula for charge Q on a capacitor is simply:
Q = CV
The formula for the energy E stored in a capacitor is:
E = 0.5CV*2
In the case where a charged cap is connected in parallel with an uncharged
one of the same rating - the resulting voltage of the combination is
found by considering the law of " conservation of charge " - that is the
CV of the combination is the SAME as the CV of the first cap.
So, the combination will have exactly half the V across it - seeing as C
has now doubled.
The mystery in the puzzle is explaining what happened to the missing
ENERGY !!
..... Phil
"Ian Macmillan"
Have a look at my blog - there might be something of interest there:
merlins-mutterings.blogspot.com
** Oh dear - your very first item has a serious math error.
"Phil Allison"
"Ian Macmillan"
Have a look at my blog - there might be something of interest there:
merlins-mutterings.blogspot.com
** Oh dear - your very first item has a serious math error.
** Dear me - I must have upset the man.
He's pulled the item ...
.. Phil
Well, it obviously needs revision.
charged and uncharged capacitors. Initially when connected the uncharged"Ian Macmillan"
"Phil Allison"
Have a look at my blog - there might be something of interest there:
merlins-mutterings.blogspot.com
** Oh dear - your very first item has a serious math error.
The formula for charge Q on a capacitor is simply:
Q = CV
The formula for the energy E stored in a capacitor is:
E = 0.5CV*2
In the case where a charged cap is connected in parallel with an
uncharged
one of the same rating - the resulting voltage of the combination is
found by considering the law of " conservation of charge " - that is
the
CV
of the combination is the SAME as the CV of the first cap.
So, the combination will have exactly half the V across it - seeing as
C
has now doubled.
The mystery in the puzzle is explaining what happened to the missing
ENERGY !!
Silly me, confusing symbols mainly. But I did point out that the mystery
energy loss was in the discharge path,
** Where is that pointed out ?
What sort of losses are you alleging go on ?
which was the point of the article.
** Fraid it does not have much of one.
Be instructive to connect a scope across the uncharged cap and observe
what
really happens when the charged one is first connected. Try a couple of
1uF
film caps.
.... Phil
What really happens depends on the resistance of the path between the
** That is the scenario posed in text book examples of the question."Phil Allison"
Be instructive to connect a scope across the uncharged cap and observe
what really happens when the charged one is first connected. Try a
couple of
1uF film caps.
What really happens depends on the resistance of the path between the
charged and uncharged capacitors. Initially when connected the uncharged
capacitor is at 0 volts, so the current that initially flows is E/R,
asymtoting to zero when the capacitor voltages match. With your 1uF film
caps, there could be an oscillation, particularly if you just shorted them
together.
** In practical caps, the high frequency ESR and Q values are crucial to theIf you just short the
capacitors together, the resistance is in the connection or internal in
the
caps - its low and the current is high but it works out the same.
** Please don't lose any sleep over it .I am
unhappy with my piece which was badly done, and I'll re-do it in due
course.
As to the point of it, obviously none for you, but could be relevant for
others.
By the way, your response also has a math error.
"Phil Allison" <phil_a@tpg.com.au> wrote in message
news:8rhb84FkheU1@mid.individual.net...
"Phil Allison"
"Ian Macmillan"
Have a look at my blog - there might be something of interest
there:
merlins-mutterings.blogspot.com
** Oh dear - your very first item has a serious math error.
** Dear me - I must have upset the man.
He's pulled the item ...
.. Phil
Well, it obviously needs revision.
Ian
** Oh dear Phil, your 2nd formula has a serious math error;
E = 0.5CV^2 NOT E = 0.5CV*2
A lot if 'interesting stuff' is incorrect, and that needs to"Ian Macmillan" <iandmac@tpg.com.au> wrote in message news:4d53b4a3@dnews.tpgi.com.au...
"Phil Allison" <phil_a@tpg.com.au> wrote in message
news:8rhb84FkheU1@mid.individual.net...
"Phil Allison"
"Ian Macmillan"
Have a look at my blog - there might be something of interest there:
merlins-mutterings.blogspot.com
** Oh dear - your very first item has a serious math error.
** Dear me - I must have upset the man.
He's pulled the item ...
.. Phil
Well, it obviously needs revision.
Ian
Good on you Ian. Without guys like yourself willing to stick some interesting stuff up on the net, the net would not be what it is
today.
True and errors can always be politely raised."Dennis" <noone@nowhere.com> wrote in message
news:jtudnUWhiJ6vIc7QnZ2dnUVZ_vSdnZ2d@westnet.com.au...
"Ian Macmillan" <iandmac@tpg.com.au> wrote in message
news:4d53b4a3@dnews.tpgi.com.au...
"Phil Allison" <phil_a@tpg.com.au> wrote in message
news:8rhb84FkheU1@mid.individual.net...
"Phil Allison"
"Ian Macmillan"
Have a look at my blog - there might be something of interest
there:
merlins-mutterings.blogspot.com
** Oh dear - your very first item has a serious math error.
** Dear me - I must have upset the man.
He's pulled the item ...
.. Phil
Well, it obviously needs revision.
Ian
Good on you Ian. Without guys like yourself willing to stick some
interesting stuff up on the net, the net would not be what it is
today.
A lot if 'interesting stuff' is incorrect, and that needs to
be pointed out, too.