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This seems to work on SPICE.Obviously a low frequency is better in determining, say, impedance but
supposing you are stuck with a higher frequency?
Couldn't you just squelch the voltage and current signals when the
second derivative of current is above a threshold?
Obviously a low frequency is better in determining, say, impedance but
supposing you are stuck with a higher frequency?
That seems fairly non-obvious to me. how is a low frequency better forObviously a low frequency is better in determining, say, impedance but
supposing you are stuck with a higher frequency?
I'm tring to picture a squelch switching at some high frequency andCouldn't you just squelch the voltage and current signals when the
second derivative of current is above a threshold?
Somehow "inductance" got left out.Obviously a low frequency is better in determining, say, impedance but
supposing you are stuck with a higher frequency?
That seems fairly non-obvious to me. how is a low frequency better for
measuring the impedance of a twisted pair?
The squelch working at a high frequency.Couldn't you just squelch the voltage and current signals when the
second derivative of current is above a threshold?
I'm tring to picture a squelch switching at some high frequency and
failing. Perhaps you mean something different?
That is evident. where was it supposed to go?Obviously a low frequency is better in determining, say, impedance but
supposing you are stuck with a higher frequency?
That seems fairly non-obvious to me. how is a low frequency better for
measuring the impedance of a twisted pair?
Somehow "inductance" got left out.
That sounds like a great way to inject noise at a yet higher frequencyCouldn't you just squelch the voltage and current signals when the
second derivative of current is above a threshold?
I'm tring to picture a squelch switching at some high frequency and
failing. Â Perhaps you mean something different?
The squelch working at a high frequency.
Whenever the absolute value of the 2nd derivative of current, or for
that matter, the absolute value of the 1st derivative of voltage, is
above a threshold value both voltage and current signals are set to
zero.
Would that be true if the squelching was digital?Obviously a low frequency is better in determining, say, impedance but
supposing you are stuck with a higher frequency?
That seems fairly non-obvious to me. how is a low frequency better for
measuring the impedance of a twisted pair?
Somehow "inductance" got left out.
That is evident. where was it supposed to go?
Couldn't you just squelch the voltage and current signals when the
second derivative of current is above a threshold?
I'm tring to picture a squelch switching at some high frequency and
failing. Perhaps you mean something different?
The squelch working at a high frequency.
Whenever the absolute value of the 2nd derivative of current, or for
that matter, the absolute value of the 1st derivative of voltage, is
above a threshold value both voltage and current signals are set to
zero.
That sounds like a great way to inject noise at a yet higher frequency
into an otherwise working system
To get the inductance.I can't immagine whay you'd want to
do that.
Yes, I squelch from time to time, esp when I read my electricity bill.Obviously a low frequency is better in determining, say, impedance but
supposing you are stuck with a higher frequency?
That seems fairly non-obvious to me. how is a low frequency better for
measuring the impedance of a twisted pair?
Somehow "inductance" got left out.
That is evident. where was it supposed to go?
Couldn't you just squelch the voltage and current signals when the
second derivative of current is above a threshold?
I'm tring to picture a squelch switching at some high frequency and
failing. Perhaps you mean something different?
The squelch working at a high frequency.
Whenever the absolute value of the 2nd derivative of current, or for
that matter, the absolute value of the 1st derivative of voltage, is
above a threshold value both voltage and current signals are set to
zero.
That sounds like a great way to inject noise at a yet higher frequency
into an otherwise working system
Would that be true if the squelching was digital?
I can't immagine whay you'd want to
do that.
To get the inductance.
Bret Cahill
I've obviously come in late here in comp.dsp, so there may beObviously a low frequency is better in determining, say, impedance but
supposing you are stuck with a higher frequency?
That seems fairly non-obvious to me. how is a low frequency better for
measuring the impedance of a twisted pair?
Somehow "inductance" got left out.
That is evident. where was it supposed to go?
Couldn't you just squelch the voltage and current signals when the
second derivative of current is above a threshold?
I'm tring to picture a squelch switching at some high frequency and
failing. Perhaps you mean something different?
The squelch working at a high frequency.
Whenever the absolute value of the 2nd derivative of current, or for
that matter, the absolute value of the 1st derivative of voltage, is
above a threshold value both voltage and current signals are set to
zero.
That sounds like a great way to inject noise at a yet higher frequency
into an otherwise working system
Would that be true if the squelching was digital?
I can't immagine whay you'd want to
do that.
To get the inductance.
Bret Cahill
You are only shutting them down when their eyes could wander.Obviously a low frequency is better in determining, say, impedance but
supposing you are stuck with a higher frequency?
That seems fairly non-obvious to me. how is a low frequency better for
measuring the impedance of a twisted pair?
Somehow "inductance" got left out.
That is evident. where was it supposed to go?
Couldn't you just squelch the voltage and current signals when the
second derivative of current is above a threshold?
I'm tring to picture a squelch switching at some high frequency and
failing. Perhaps you mean something different?
The squelch working at a high frequency.
Whenever the absolute value of the 2nd derivative of current, or for
that matter, the absolute value of the 1st derivative of voltage, is
above a threshold value both voltage and current signals are set to
zero.
That sounds like a great way to inject noise at a yet higher frequency
into an otherwise working system
Would that be true if the squelching was digital?
I can't immagine whay you'd want to
do that.
To get the inductance.
Bret Cahill
I've obviously come in late here in comp.dsp, so there may be
something I missed that would make this rational. As it stands with
me, the question is ludicrous. You are evidently attempting to make an
electrical measurement by blinding your instruments to both voltage
and current. Can you explain how that's assumed to work?
How does that get you the information you want?Obviously a low frequency is better in determining, say, impedance but
supposing you are stuck with a higher frequency?
That seems fairly non-obvious to me. how is a low frequency better for
measuring the impedance of a twisted pair?
Somehow "inductance" got left out.
That is evident. where was it supposed to go?
Couldn't you just squelch the voltage and current signals when the
second derivative of current is above a threshold?
I'm tring to picture a squelch switching at some high frequency and
failing. Perhaps you mean something different?
The squelch working at a high frequency.
Whenever the absolute value of the 2nd derivative of current, or for
that matter, the absolute value of the 1st derivative of voltage, is
above a threshold value both voltage and current signals are set to
zero.
That sounds like a great way to inject noise at a yet higher frequency
into an otherwise working system
Would that be true if the squelching was digital?
I can't immagine whay you'd want to
do that.
To get the inductance.
Bret Cahill
I've obviously come in late here in comp.dsp, so there may be
something I missed that would make this rational. As it stands with
me, the question is ludicrous. You are evidently attempting to make an
electrical measurement by blinding your instruments to both voltage
and current. Can you explain how that's assumed to work?
You are only shutting them down when their eyes could wander.
Just as you don't need all the frequencies and you don't need all ofObviously a low frequency is better in determining, say, impedance but
supposing you are stuck with a higher frequency?
That seems fairly non-obvious to me. how is a low frequency better for
measuring the impedance of a twisted pair?
Somehow "inductance" got left out.
That is evident. where was it supposed to go?
Couldn't you just squelch the voltage and current signals when the
second derivative of current is above a threshold?
I'm tring to picture a squelch switching at some high frequency and
failing. Perhaps you mean something different?
The squelch working at a high frequency.
Whenever the absolute value of the 2nd derivative of current, or for
that matter, the absolute value of the 1st derivative of voltage, is
above a threshold value both voltage and current signals are set to
zero.
That sounds like a great way to inject noise at a yet higher frequency
into an otherwise working system
Would that be true if the squelching was digital?
I can't immagine whay you'd want to
do that.
To get the inductance.
Bret Cahill
I've obviously come in late here in comp.dsp, so there may be
something I missed that would make this rational. As it stands with
me, the question is ludicrous. You are evidently attempting to make an
electrical measurement by blinding your instruments to both voltage
and current. Can you explain how that's assumed to work?
You are only shutting them down when their eyes could wander.
How does that get you the information you want?
On Apr 17, 2:36 pm, Bret Cahill <Bret_E_Cah...@yahoo.com> wrote:
Obviously a low frequency is better in determining, say, impedance but
supposing you are stuck with a higher frequency?
That seems fairly non-obvious to me. how is a low frequency better for
measuring the impedance of a twisted pair?
Somehow "inductance" got left out.
That is evident. where was it supposed to go?
Couldn't you just squelch the voltage and current signals when the
second derivative of current is above a threshold?
I'm tring to picture a squelch switching at some high frequency and
failing. Perhaps you mean something different?
The squelch working at a high frequency.
Whenever the absolute value of the 2nd derivative of current, or for
that matter, the absolute value of the 1st derivative of voltage, is
above a threshold value both voltage and current signals are set to
zero.
That sounds like a great way to inject noise at a yet higher frequency
into an otherwise working system
Would that be true if the squelching was digital?
I can't immagine whay you'd want to
do that.
To get the inductance.
Bret Cahill
I've obviously come in late here in comp.dsp, so there may be
something I missed that would make this rational. As it stands with
me, the question is ludicrous. You are evidently attempting to make an
electrical measurement by blinding your instruments to both voltage
and current. Can you explain how that's assumed to work?
You are only shutting them down when their eyes could wander.
How does that get you the information you want?
Just as you don't need all the frequencies and you don't need all of
the cycle of any one frequency either.
Whatever you need or don't, how does squelching provide more
information?
You can select just the parts of the cycle where the noise is lowest
or, in this case, the current bleeding off through resistances and
capacitances is lowest.
...
You sample the data, so instead of squelching the signal, why not
simply ignore the samples you don't want? In any case, the current
will be lowest when the voltage Resistance) or its derivative
(capacitance) is.
Whatever you need or don't, how does squelching provide moreObviously a low frequency is better in determining, say, impedance but
supposing you are stuck with a higher frequency?
That seems fairly non-obvious to me. how is a low frequency better for
measuring the impedance of a twisted pair?
Somehow "inductance" got left out.
That is evident. where was it supposed to go?
Couldn't you just squelch the voltage and current signals when the
second derivative of current is above a threshold?
I'm tring to picture a squelch switching at some high frequency and
failing. Perhaps you mean something different?
The squelch working at a high frequency.
Whenever the absolute value of the 2nd derivative of current, or for
that matter, the absolute value of the 1st derivative of voltage, is
above a threshold value both voltage and current signals are set to
zero.
That sounds like a great way to inject noise at a yet higher frequency
into an otherwise working system
Would that be true if the squelching was digital?
I can't immagine whay you'd want to
do that.
To get the inductance.
Bret Cahill
I've obviously come in late here in comp.dsp, so there may be
something I missed that would make this rational. As it stands with
me, the question is ludicrous. You are evidently attempting to make an
electrical measurement by blinding your instruments to both voltage
and current. Can you explain how that's assumed to work?
You are only shutting them down when their eyes could wander.
How does that get you the information you want?
Just as you don't need all the frequencies and you don't need all of
the cycle of any one frequency either.
...You can select just the parts of the cycle where the noise is lowest
or, in this case, the current bleeding off through resistances and
capacitances is lowest.
Well it provides _less wrong_ information, same as low pass filteringObviously a low frequency is better in determining, say, impedance but
supposing you are stuck with a higher frequency?
That seems fairly non-obvious to me. how is a low frequency better for
measuring the impedance of a twisted pair?
Somehow "inductance" got left out.
That is evident. where was it supposed to go?
Couldn't you just squelch the voltage and current signals when the
second derivative of current is above a threshold?
I'm tring to picture a squelch switching at some high frequency and
failing. Perhaps you mean something different?
The squelch working at a high frequency.
Whenever the absolute value of the 2nd derivative of current, or for
that matter, the absolute value of the 1st derivative of voltage, is
above a threshold value both voltage and current signals are set to
zero.
That sounds like a great way to inject noise at a yet higher frequency
into an otherwise working system
Would that be true if the squelching was digital?
I can't immagine whay you'd want to
do that.
To get the inductance.
Bret Cahill
I've obviously come in late here in comp.dsp, so there may be
something I missed that would make this rational. As it stands with
me, the question is ludicrous. You are evidently attempting to make an
electrical measurement by blinding your instruments to both voltage
and current. Can you explain how that's assumed to work?
You are only shutting them down when their eyes could wander.
How does that get you the information you want?
Just as you don't need all the frequencies and you don't need all of
the cycle of any one frequency either.
Whatever you need or don't, how does squelching provide more
information?
Is that really any different than squelching?You can select just the parts of the cycle where the noise is lowest
or, in this case, the current bleeding off through resistances and
capacitances is lowest.
You sample the data, so instead of squelching the signal, why not
simply ignore the samples you don't want?
is highest?In any case, the current
will be lowest when the voltage Resistance) or its derivative
(capacitance) is.