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For an astable multivibrator, would 2n7000 mosfets be more efficient than 2n3904 bjts?
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On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:
For an astable multivibrator, would 2n7000 mosfets be more efficient
than 2n3904 bjts?
How long is a string?
--
www.wescottdesign.com
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:
For an astable multivibrator, would 2n7000 mosfets be more efficient
than 2n3904 bjts?
How long is a string?
--
www.wescottdesign.com
0 <= L < oo ?
I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.
Without any more detail than that, no correct answer can be given, any
more than one can answer "how long is a string?".
Post a circuit, and what you're trying to do with it, and we'll try to
help out -- even if we have to start by asking for more detail yet.
--
Tim Wescott
Wescott Design Services
http://www.wescottdesign.com
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:
For an astable multivibrator, would 2n7000 mosfets be more efficient
than 2n3904 bjts?
How long is a string?
--
www.wescottdesign.com
0 <= L < oo ?
I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.
Without any more detail than that, no correct answer can be given, any
more than one can answer "how long is a string?".
Post a circuit, and what you're trying to do with it, and we'll try to
help out -- even if we have to start by asking for more detail yet.
--
Tim Wescott
Wescott Design Services
http://www.wescottdesign.com
A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/File:Transistor_Multivibrator.svg
R1=R4=10k
R2=R3=10k
C1=C2=0.1uF
Q1=Q2=2n3904 or 2n7000 (which is why I asked)
I'm tapping into the node between R4 and Q2's collector to run the gate of a MOSFET (irf530) to power a blower motor.
Michael
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:
For an astable multivibrator, would 2n7000 mosfets be more efficient
than 2n3904 bjts?
How long is a string?
--
www.wescottdesign.com
0 <= L < oo ?
I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.
Without any more detail than that, no correct answer can be given, any
more than one can answer "how long is a string?".
Post a circuit, and what you're trying to do with it, and we'll try to
help out -- even if we have to start by asking for more detail yet.
--
Tim Wescott
Wescott Design Services
http://www.wescottdesign.com
A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/File:Transistor_Multivibrator.svg
R1=R4=10k
R2=R3=10k
C1=C2=0.1uF
Q1=Q2=2n3904 or 2n7000 (which is why I asked)
I'm tapping into the node between R4 and Q2's collector to run the gate of a MOSFET (irf530) to power a blower motor.
Michael
On Wed, 17 Dec 2014 13:47:53 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 1:40:26 PM UTC-8, mrda...@gmail.com
wrote:
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:
For an astable multivibrator, would 2n7000 mosfets be more
efficient than 2n3904 bjts?
How long is a string?
--
www.wescottdesign.com
0 <= L < oo ?
I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.
Without any more detail than that, no correct answer can be given,
any more than one can answer "how long is a string?".
Post a circuit, and what you're trying to do with it, and we'll try
to help out -- even if we have to start by asking for more detail
yet.
--
Tim Wescott Wescott Design Services http://www.wescottdesign.com
A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/
File:Transistor_Multivibrator.svg
R1=R4=10k R2=R3=10k C1=C2=0.1uF Q1=Q2=2n3904 or 2n7000 (which is why I
asked)
I'm tapping into the node between R4 and Q2's collector to run the gate
of a MOSFET (irf530) to power a blower motor.
Michael
Sorry, R2=R3=60k
If that circuit ever got into a situation where both transistors were
turned on, they would saturate, both their collectors would be sitting at
low voltages, and the base current delivered by R2 and R3 would be
sufficient to keep them saturated.
Moreover, that circuit depends on the base current of a BJT to work: with
a pair of FETs, the average voltage of the gates will rise to equal the
supply voltage, they'll both end up turned on hard, and the circuit won't
work.
You could come up with more elaborate biasing arrangements -- but why?
A 555 will work at 12V -- why not use a 555 and a 12V linear regulator?
You should get plenty of drive to your MOSFET gate, and you'll have a
circuit that won't fail 0.1% of the time, while leaving you unable to
diagnose problems the other 99.9%.
To answer your original question: the base current of the BJT's is small
compared to the power getting burnt in the resistors; the reduced power
consumption (if any) would be lost in the noise of component variations
from unit to unit.
--
Tim Wescott
Wescott Design Services
http://www.wescottdesign.com
For an astable multivibrator, would 2n7000 mosfets be more efficient
than 2n3904 bjts?
But what's the context? Most people wouldn't fuss over efficiency. In aOn Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:
For an astable multivibrator, would 2n7000 mosfets be more efficient
than 2n3904 bjts?
How long is a string?
--
www.wescottdesign.com
0 <= L < oo ?
I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.
On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:
For an astable multivibrator, would 2n7000 mosfets be more efficient
than 2n3904 bjts?
How long is a string?
--
www.wescottdesign.com
0 <= L < oo ?
I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.
On Wednesday, December 17, 2014 1:40:26 PM UTC-8, mrda...@gmail.com
wrote:
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:
For an astable multivibrator, would 2n7000 mosfets be more
efficient than 2n3904 bjts?
How long is a string?
--
www.wescottdesign.com
0 <= L < oo ?
I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.
Without any more detail than that, no correct answer can be given,
any more than one can answer "how long is a string?".
Post a circuit, and what you're trying to do with it, and we'll try
to help out -- even if we have to start by asking for more detail
yet.
--
Tim Wescott Wescott Design Services http://www.wescottdesign.com
A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/
File:Transistor_Multivibrator.svg
R1=R4=10k R2=R3=10k C1=C2=0.1uF Q1=Q2=2n3904 or 2n7000 (which is why I
asked)
I'm tapping into the node between R4 and Q2's collector to run the gate
of a MOSFET (irf530) to power a blower motor.
Michael
Sorry, R2=R3=60k
On Wed, 17 Dec 2014 14:37:58 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 2:14:30 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 13:47:53 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 1:40:26 PM UTC-8, mrda...@gmail.com
wrote:
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:
For an astable multivibrator, would 2n7000 mosfets be more
efficient than 2n3904 bjts?
How long is a string?
--
www.wescottdesign.com
0 <= L < oo ?
I built one with 2n3904s and was wondering if I should order
some 2n7000s from Mouser to make it more efficient, is all.
Without any more detail than that, no correct answer can be given,
any more than one can answer "how long is a string?".
Post a circuit, and what you're trying to do with it, and we'll
try to help out -- even if we have to start by asking for more
detail yet.
--
Tim Wescott Wescott Design Services http://www.wescottdesign.com
A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/
File:Transistor_Multivibrator.svg
R1=R4=10k R2=R3=10k C1=C2=0.1uF Q1=Q2=2n3904 or 2n7000 (which is why
I asked)
I'm tapping into the node between R4 and Q2's collector to run the
gate of a MOSFET (irf530) to power a blower motor.
Michael
Sorry, R2=R3=60k
If that circuit ever got into a situation where both transistors were
turned on, they would saturate, both their collectors would be sitting
at low voltages, and the base current delivered by R2 and R3 would be
sufficient to keep them saturated.
Moreover, that circuit depends on the base current of a BJT to work:
with a pair of FETs, the average voltage of the gates will rise to
equal the supply voltage, they'll both end up turned on hard, and the
circuit won't work.
You could come up with more elaborate biasing arrangements -- but why?
A 555 will work at 12V -- why not use a 555 and a 12V linear regulator?
You should get plenty of drive to your MOSFET gate, and you'll have a
circuit that won't fail 0.1% of the time, while leaving you unable to
diagnose problems the other 99.9%.
To answer your original question: the base current of the BJT's is
small compared to the power getting burnt in the resistors; the reduced
power consumption (if any) would be lost in the noise of component
variations from unit to unit.
--
Tim Wescott Wescott Design Services http://www.wescottdesign.com
Ah, ok. So, to summarize, did I understand this correctly:
1) the astable multivibrator circuit with discrete components requires
BJTs to operate properly; the system will not oscillate with FETs
THAT circuit needs BJTs. You could make it work with FETs, at the cost of
having to use more resistors.
2) there is a 0.1% probability of the system failing to oscillate; use a
555 to avoid this
Again, you could make the circuit more elaborate and stick with
transistors -- but a 555 will just get 'er done.
3) to reduce power consumption, increase R1 and R4
Why... I just get a kick out of using discrete transistors instead of an
IC. That's why.
I know. IC's are boring. But they're a "I haven't been screamed at by a
customer for months now" kind of boring, which to my mind is a _good_ kind
of boring.
--
Tim Wescott
Wescott Design Services
http://www.wescottdesign.com
On Wednesday, December 17, 2014 2:14:30 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 13:47:53 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 1:40:26 PM UTC-8, mrda...@gmail.com
wrote:
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:
For an astable multivibrator, would 2n7000 mosfets be more
efficient than 2n3904 bjts?
How long is a string?
--
www.wescottdesign.com
0 <= L < oo ?
I built one with 2n3904s and was wondering if I should order
some 2n7000s from Mouser to make it more efficient, is all.
Without any more detail than that, no correct answer can be given,
any more than one can answer "how long is a string?".
Post a circuit, and what you're trying to do with it, and we'll
try to help out -- even if we have to start by asking for more
detail yet.
--
Tim Wescott Wescott Design Services http://www.wescottdesign.com
A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/
File:Transistor_Multivibrator.svg
R1=R4=10k R2=R3=10k C1=C2=0.1uF Q1=Q2=2n3904 or 2n7000 (which is why
I asked)
I'm tapping into the node between R4 and Q2's collector to run the
gate of a MOSFET (irf530) to power a blower motor.
Michael
Sorry, R2=R3=60k
If that circuit ever got into a situation where both transistors were
turned on, they would saturate, both their collectors would be sitting
at low voltages, and the base current delivered by R2 and R3 would be
sufficient to keep them saturated.
Moreover, that circuit depends on the base current of a BJT to work:
with a pair of FETs, the average voltage of the gates will rise to
equal the supply voltage, they'll both end up turned on hard, and the
circuit won't work.
You could come up with more elaborate biasing arrangements -- but why?
A 555 will work at 12V -- why not use a 555 and a 12V linear regulator?
You should get plenty of drive to your MOSFET gate, and you'll have a
circuit that won't fail 0.1% of the time, while leaving you unable to
diagnose problems the other 99.9%.
To answer your original question: the base current of the BJT's is
small compared to the power getting burnt in the resistors; the reduced
power consumption (if any) would be lost in the noise of component
variations from unit to unit.
--
Tim Wescott Wescott Design Services http://www.wescottdesign.com
Ah, ok. So, to summarize, did I understand this correctly:
1) the astable multivibrator circuit with discrete components requires
BJTs to operate properly; the system will not oscillate with FETs
2) there is a 0.1% probability of the system failing to oscillate; use a
555 to avoid this
3) to reduce power consumption, increase R1 and R4
Why... I just get a kick out of using discrete transistors instead of an
IC. That's why.
On Wednesday, December 17, 2014 2:14:30 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 13:47:53 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 1:40:26 PM UTC-8, mrda...@gmail.com
wrote:
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:
For an astable multivibrator, would 2n7000 mosfets be more
efficient than 2n3904 bjts?
How long is a string?
--
www.wescottdesign.com
0 <= L < oo ?
I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.
Without any more detail than that, no correct answer can be given,
any more than one can answer "how long is a string?".
Post a circuit, and what you're trying to do with it, and we'll try
to help out -- even if we have to start by asking for more detail
yet.
--
Tim Wescott Wescott Design Services http://www.wescottdesign.com
A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/
File:Transistor_Multivibrator.svg
R1=R4=10k R2=R3=10k C1=C2=0.1uF Q1=Q2=2n3904 or 2n7000 (which is why I
asked)
I'm tapping into the node between R4 and Q2's collector to run the gate
of a MOSFET (irf530) to power a blower motor.
Michael
Sorry, R2=R3=60k
If that circuit ever got into a situation where both transistors were
turned on, they would saturate, both their collectors would be sitting at
low voltages, and the base current delivered by R2 and R3 would be
sufficient to keep them saturated.
Moreover, that circuit depends on the base current of a BJT to work: with
a pair of FETs, the average voltage of the gates will rise to equal the
supply voltage, they'll both end up turned on hard, and the circuit won't
work.
You could come up with more elaborate biasing arrangements -- but why?
A 555 will work at 12V -- why not use a 555 and a 12V linear regulator?
You should get plenty of drive to your MOSFET gate, and you'll have a
circuit that won't fail 0.1% of the time, while leaving you unable to
diagnose problems the other 99.9%.
To answer your original question: the base current of the BJT's is small
compared to the power getting burnt in the resistors; the reduced power
consumption (if any) would be lost in the noise of component variations
from unit to unit.
--
Tim Wescott
Wescott Design Services
http://www.wescottdesign.com
Ah, ok. So, to summarize, did I understand this correctly:
1) the astable multivibrator circuit with discrete components requires BJTs to operate properly; the system will not oscillate with FETs
2) there is a 0.1% probability of the system failing to oscillate; use a 555 to avoid this
3) to reduce power consumption, increase R1 and R4
Why... I just get a kick out of using discrete transistors instead of an IC. That's why.
Thanks!
Michael
On Wed, 17 Dec 2014 14:37:58 -0800 (PST), mrdarrett@gmail.com wrote:
On Wednesday, December 17, 2014 2:14:30 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 13:47:53 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 1:40:26 PM UTC-8, mrda...@gmail.com
wrote:
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:
On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:
For an astable multivibrator, would 2n7000 mosfets be more
efficient than 2n3904 bjts?
How long is a string?
--
www.wescottdesign.com
0 <= L < oo ?
I built one with 2n3904s and was wondering if I should order
some 2n7000s from Mouser to make it more efficient, is all.
Without any more detail than that, no correct answer can be
given, any more than one can answer "how long is a string?".
Post a circuit, and what you're trying to do with it, and we'll
try to help out -- even if we have to start by asking for more
detail yet.
--
Tim Wescott Wescott Design Services http://www.wescottdesign.com
A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/
File:Transistor_Multivibrator.svg
R1=R4=10k R2=R3=10k C1=C2=0.1uF Q1=Q2=2n3904 or 2n7000 (which is
why I asked)
I'm tapping into the node between R4 and Q2's collector to run the
gate of a MOSFET (irf530) to power a blower motor.
Michael
Sorry, R2=R3=60k
If that circuit ever got into a situation where both transistors were
turned on, they would saturate, both their collectors would be sitting
at low voltages, and the base current delivered by R2 and R3 would be
sufficient to keep them saturated.
Moreover, that circuit depends on the base current of a BJT to work:
with a pair of FETs, the average voltage of the gates will rise to
equal the supply voltage, they'll both end up turned on hard, and the
circuit won't work.
You could come up with more elaborate biasing arrangements -- but why?
A 555 will work at 12V -- why not use a 555 and a 12V linear
regulator? You should get plenty of drive to your MOSFET gate, and
you'll have a circuit that won't fail 0.1% of the time, while leaving
you unable to diagnose problems the other 99.9%.
To answer your original question: the base current of the BJT's is
small compared to the power getting burnt in the resistors; the
reduced power consumption (if any) would be lost in the noise of
component variations from unit to unit.
--
Tim Wescott Wescott Design Services http://www.wescottdesign.com
Ah, ok. So, to summarize, did I understand this correctly:
1) the astable multivibrator circuit with discrete components requires
BJTs to operate properly; the system will not oscillate with FETs
2) there is a 0.1% probability of the system failing to oscillate; use a
555 to avoid this
3) to reduce power consumption, increase R1 and R4
Why... I just get a kick out of using discrete transistors instead of an
IC. That's why.
Thanks!
Michael
With 12 volts or so Vcc, you'll be zenering the bipolar b-e junctions,
which is A Bad Thing. Spice will typically not model b-e breakdown.
On Wednesday, December 17, 2014 10:14:16 AM UTC-8, mrda...@gmail.com wrote:
For an astable multivibrator, would 2n7000 mosfets be more efficient than 2n3904 bjts?
No, considerably less efficient. One cannot get as good power gain from a
MOSFET with very low drain current as one can from a bipolar transistor.
So, for any target transition slew rate, a power advantage will accrue to the
bipolar design variant. You also get lower tolerances on turn-on threshold
voltage (so can design for lower power supply voltages).
To play with these ideas, get LTspice or some similar simulator, and plug
in some device models, and ... start evaluating designs in simulation.
In particular, for power efficiency, crank down the applied voltage or
raise all the resistor values, until something breaks.
With 12 volts or so Vcc, you'll be zenering the bipolar b-e junctions,
which is A Bad Thing. Spice will typically not model b-e breakdown.
--
John Larkin Highland Technology, Inc
picosecond timing precision measurement
jlarkin att highlandtechnology dott com
http://www.highlandtechnology.com
2) there is a 0.1% probability of the system failing to oscillate; use a 555 to avoid this
3) to reduce power consumption, increase R1 and R4
Why... I just get a kick out of using discrete transistors instead of an IC. That's why.
Thanks!
Michael
With 12 volts or so Vcc, you'll be zenering the bipolar b-e junctions,
which is A Bad Thing. Spice will typically not model b-e breakdown.