astable multivibrator semiconductors

Guest
For an astable multivibrator, would 2n7000 mosfets be more efficient than 2n3904 bjts?
 
On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:

For an astable multivibrator, would 2n7000 mosfets be more efficient
than 2n3904 bjts?

How long is a string?

--
www.wescottdesign.com

0 <= L < oo ?

I built one with 2n3904s and was wondering if I should order some 2n7000s from Mouser to make it more efficient, is all.
 
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:

For an astable multivibrator, would 2n7000 mosfets be more efficient
than 2n3904 bjts?

How long is a string?

--
www.wescottdesign.com


0 <= L < oo ?

I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.

Without any more detail than that, no correct answer can be given, any
more than one can answer "how long is a string?".

Post a circuit, and what you're trying to do with it, and we'll try to
help out -- even if we have to start by asking for more detail yet.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com


A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/File:Transistor_Multivibrator.svg

R1=R4=10k
R2=R3=10k
C1=C2=0.1uF
Q1=Q2=2n3904 or 2n7000 (which is why I asked)

I'm tapping into the node between R4 and Q2's collector to run the gate of a MOSFET (irf530) to power a blower motor.

Michael
 
On Wednesday, December 17, 2014 1:40:26 PM UTC-8, mrda...@gmail.com wrote:
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:

For an astable multivibrator, would 2n7000 mosfets be more efficient
than 2n3904 bjts?

How long is a string?

--
www.wescottdesign.com


0 <= L < oo ?

I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.

Without any more detail than that, no correct answer can be given, any
more than one can answer "how long is a string?".

Post a circuit, and what you're trying to do with it, and we'll try to
help out -- even if we have to start by asking for more detail yet.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com



A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/File:Transistor_Multivibrator.svg

R1=R4=10k
R2=R3=10k
C1=C2=0.1uF
Q1=Q2=2n3904 or 2n7000 (which is why I asked)

I'm tapping into the node between R4 and Q2's collector to run the gate of a MOSFET (irf530) to power a blower motor.

Michael

Oh, and +V is between 12v and 18v
 
On Wednesday, December 17, 2014 1:40:26 PM UTC-8, mrda...@gmail.com wrote:
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:

For an astable multivibrator, would 2n7000 mosfets be more efficient
than 2n3904 bjts?

How long is a string?

--
www.wescottdesign.com


0 <= L < oo ?

I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.

Without any more detail than that, no correct answer can be given, any
more than one can answer "how long is a string?".

Post a circuit, and what you're trying to do with it, and we'll try to
help out -- even if we have to start by asking for more detail yet.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com



A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/File:Transistor_Multivibrator.svg

R1=R4=10k
R2=R3=10k
C1=C2=0.1uF
Q1=Q2=2n3904 or 2n7000 (which is why I asked)

I'm tapping into the node between R4 and Q2's collector to run the gate of a MOSFET (irf530) to power a blower motor.

Michael

Sorry, R2=R3=60k
 
On Wednesday, December 17, 2014 2:14:30 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 13:47:53 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 1:40:26 PM UTC-8, mrda...@gmail.com
wrote:
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:

For an astable multivibrator, would 2n7000 mosfets be more
efficient than 2n3904 bjts?

How long is a string?

--
www.wescottdesign.com


0 <= L < oo ?

I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.

Without any more detail than that, no correct answer can be given,
any more than one can answer "how long is a string?".

Post a circuit, and what you're trying to do with it, and we'll try
to help out -- even if we have to start by asking for more detail
yet.

--

Tim Wescott Wescott Design Services http://www.wescottdesign.com



A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/
File:Transistor_Multivibrator.svg

R1=R4=10k R2=R3=10k C1=C2=0.1uF Q1=Q2=2n3904 or 2n7000 (which is why I
asked)

I'm tapping into the node between R4 and Q2's collector to run the gate
of a MOSFET (irf530) to power a blower motor.

Michael


Sorry, R2=R3=60k

If that circuit ever got into a situation where both transistors were
turned on, they would saturate, both their collectors would be sitting at
low voltages, and the base current delivered by R2 and R3 would be
sufficient to keep them saturated.

Moreover, that circuit depends on the base current of a BJT to work: with
a pair of FETs, the average voltage of the gates will rise to equal the
supply voltage, they'll both end up turned on hard, and the circuit won't
work.

You could come up with more elaborate biasing arrangements -- but why?

A 555 will work at 12V -- why not use a 555 and a 12V linear regulator?
You should get plenty of drive to your MOSFET gate, and you'll have a
circuit that won't fail 0.1% of the time, while leaving you unable to
diagnose problems the other 99.9%.

To answer your original question: the base current of the BJT's is small
compared to the power getting burnt in the resistors; the reduced power
consumption (if any) would be lost in the noise of component variations
from unit to unit.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com

Ah, ok. So, to summarize, did I understand this correctly:

1) the astable multivibrator circuit with discrete components requires BJTs to operate properly; the system will not oscillate with FETs

2) there is a 0.1% probability of the system failing to oscillate; use a 555 to avoid this

3) to reduce power consumption, increase R1 and R4

Why... I just get a kick out of using discrete transistors instead of an IC. That's why.

Thanks!

Michael
 
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:

For an astable multivibrator, would 2n7000 mosfets be more efficient
than 2n3904 bjts?

How long is a string?

--
www.wescottdesign.com
 
On Wed, 17 Dec 2014, mrdarrett@gmail.com wrote:

On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:

For an astable multivibrator, would 2n7000 mosfets be more efficient
than 2n3904 bjts?

How long is a string?

--
www.wescottdesign.com


0 <= L < oo ?

I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.
But what's the context? Most people wouldn't fuss over efficiency. In a
handful of instances it might make sense.

Michael
 
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:

For an astable multivibrator, would 2n7000 mosfets be more efficient
than 2n3904 bjts?

How long is a string?

--
www.wescottdesign.com


0 <= L < oo ?

I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.

Without any more detail than that, no correct answer can be given, any
more than one can answer "how long is a string?".

Post a circuit, and what you're trying to do with it, and we'll try to
help out -- even if we have to start by asking for more detail yet.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com
 
On Wed, 17 Dec 2014 13:47:53 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 1:40:26 PM UTC-8, mrda...@gmail.com
wrote:
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:

For an astable multivibrator, would 2n7000 mosfets be more
efficient than 2n3904 bjts?

How long is a string?

--
www.wescottdesign.com


0 <= L < oo ?

I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.

Without any more detail than that, no correct answer can be given,
any more than one can answer "how long is a string?".

Post a circuit, and what you're trying to do with it, and we'll try
to help out -- even if we have to start by asking for more detail
yet.

--

Tim Wescott Wescott Design Services http://www.wescottdesign.com



A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/
File:Transistor_Multivibrator.svg

R1=R4=10k R2=R3=10k C1=C2=0.1uF Q1=Q2=2n3904 or 2n7000 (which is why I
asked)

I'm tapping into the node between R4 and Q2's collector to run the gate
of a MOSFET (irf530) to power a blower motor.

Michael


Sorry, R2=R3=60k

If that circuit ever got into a situation where both transistors were
turned on, they would saturate, both their collectors would be sitting at
low voltages, and the base current delivered by R2 and R3 would be
sufficient to keep them saturated.

Moreover, that circuit depends on the base current of a BJT to work: with
a pair of FETs, the average voltage of the gates will rise to equal the
supply voltage, they'll both end up turned on hard, and the circuit won't
work.

You could come up with more elaborate biasing arrangements -- but why?

A 555 will work at 12V -- why not use a 555 and a 12V linear regulator?
You should get plenty of drive to your MOSFET gate, and you'll have a
circuit that won't fail 0.1% of the time, while leaving you unable to
diagnose problems the other 99.9%.

To answer your original question: the base current of the BJT's is small
compared to the power getting burnt in the resistors; the reduced power
consumption (if any) would be lost in the noise of component variations
from unit to unit.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com
 
Most people would not fuss over efficiency? :D maybe I am just strange then.
 
On Wednesday, December 17, 2014 6:47:07 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 14:37:58 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 2:14:30 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 13:47:53 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 1:40:26 PM UTC-8, mrda...@gmail.com
wrote:
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:

For an astable multivibrator, would 2n7000 mosfets be more
efficient than 2n3904 bjts?

How long is a string?

--
www.wescottdesign.com


0 <= L < oo ?

I built one with 2n3904s and was wondering if I should order
some 2n7000s from Mouser to make it more efficient, is all.

Without any more detail than that, no correct answer can be given,
any more than one can answer "how long is a string?".

Post a circuit, and what you're trying to do with it, and we'll
try to help out -- even if we have to start by asking for more
detail yet.

--

Tim Wescott Wescott Design Services http://www.wescottdesign.com



A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/
File:Transistor_Multivibrator.svg

R1=R4=10k R2=R3=10k C1=C2=0.1uF Q1=Q2=2n3904 or 2n7000 (which is why
I asked)

I'm tapping into the node between R4 and Q2's collector to run the
gate of a MOSFET (irf530) to power a blower motor.

Michael


Sorry, R2=R3=60k

If that circuit ever got into a situation where both transistors were
turned on, they would saturate, both their collectors would be sitting
at low voltages, and the base current delivered by R2 and R3 would be
sufficient to keep them saturated.

Moreover, that circuit depends on the base current of a BJT to work:
with a pair of FETs, the average voltage of the gates will rise to
equal the supply voltage, they'll both end up turned on hard, and the
circuit won't work.

You could come up with more elaborate biasing arrangements -- but why?

A 555 will work at 12V -- why not use a 555 and a 12V linear regulator?
You should get plenty of drive to your MOSFET gate, and you'll have a
circuit that won't fail 0.1% of the time, while leaving you unable to
diagnose problems the other 99.9%.

To answer your original question: the base current of the BJT's is
small compared to the power getting burnt in the resistors; the reduced
power consumption (if any) would be lost in the noise of component
variations from unit to unit.

--

Tim Wescott Wescott Design Services http://www.wescottdesign.com


Ah, ok. So, to summarize, did I understand this correctly:

1) the astable multivibrator circuit with discrete components requires
BJTs to operate properly; the system will not oscillate with FETs

THAT circuit needs BJTs. You could make it work with FETs, at the cost of
having to use more resistors.

2) there is a 0.1% probability of the system failing to oscillate; use a
555 to avoid this

Again, you could make the circuit more elaborate and stick with
transistors -- but a 555 will just get 'er done.

3) to reduce power consumption, increase R1 and R4

Why... I just get a kick out of using discrete transistors instead of an
IC. That's why.

I know. IC's are boring. But they're a "I haven't been screamed at by a
customer for months now" kind of boring, which to my mind is a _good_ kind
of boring.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com

Oh, alright. :) I was bored while on vacation a couple years ago and modified an astable multivibrator into a PWM motor controller. I thought it was kind of cute, just using two 2n3904s (and of course a power mosfet for the motor).

Noted. Failure to oscillate could be bad. For experimental use only :D

Michael
 
On Wed, 17 Dec 2014 14:37:58 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 2:14:30 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 13:47:53 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 1:40:26 PM UTC-8, mrda...@gmail.com
wrote:
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:

For an astable multivibrator, would 2n7000 mosfets be more
efficient than 2n3904 bjts?

How long is a string?

--
www.wescottdesign.com


0 <= L < oo ?

I built one with 2n3904s and was wondering if I should order
some 2n7000s from Mouser to make it more efficient, is all.

Without any more detail than that, no correct answer can be given,
any more than one can answer "how long is a string?".

Post a circuit, and what you're trying to do with it, and we'll
try to help out -- even if we have to start by asking for more
detail yet.

--

Tim Wescott Wescott Design Services http://www.wescottdesign.com



A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/
File:Transistor_Multivibrator.svg

R1=R4=10k R2=R3=10k C1=C2=0.1uF Q1=Q2=2n3904 or 2n7000 (which is why
I asked)

I'm tapping into the node between R4 and Q2's collector to run the
gate of a MOSFET (irf530) to power a blower motor.

Michael


Sorry, R2=R3=60k

If that circuit ever got into a situation where both transistors were
turned on, they would saturate, both their collectors would be sitting
at low voltages, and the base current delivered by R2 and R3 would be
sufficient to keep them saturated.

Moreover, that circuit depends on the base current of a BJT to work:
with a pair of FETs, the average voltage of the gates will rise to
equal the supply voltage, they'll both end up turned on hard, and the
circuit won't work.

You could come up with more elaborate biasing arrangements -- but why?

A 555 will work at 12V -- why not use a 555 and a 12V linear regulator?
You should get plenty of drive to your MOSFET gate, and you'll have a
circuit that won't fail 0.1% of the time, while leaving you unable to
diagnose problems the other 99.9%.

To answer your original question: the base current of the BJT's is
small compared to the power getting burnt in the resistors; the reduced
power consumption (if any) would be lost in the noise of component
variations from unit to unit.

--

Tim Wescott Wescott Design Services http://www.wescottdesign.com


Ah, ok. So, to summarize, did I understand this correctly:

1) the astable multivibrator circuit with discrete components requires
BJTs to operate properly; the system will not oscillate with FETs

THAT circuit needs BJTs. You could make it work with FETs, at the cost of
having to use more resistors.

2) there is a 0.1% probability of the system failing to oscillate; use a
555 to avoid this

Again, you could make the circuit more elaborate and stick with
transistors -- but a 555 will just get 'er done.

3) to reduce power consumption, increase R1 and R4

Why... I just get a kick out of using discrete transistors instead of an
IC. That's why.

I know. IC's are boring. But they're a "I haven't been screamed at by a
customer for months now" kind of boring, which to my mind is a _good_ kind
of boring.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com
 
On Wed, 17 Dec 2014 14:37:58 -0800 (PST), mrdarrett@gmail.com wrote:

On Wednesday, December 17, 2014 2:14:30 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 13:47:53 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 1:40:26 PM UTC-8, mrda...@gmail.com
wrote:
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:

For an astable multivibrator, would 2n7000 mosfets be more
efficient than 2n3904 bjts?

How long is a string?

--
www.wescottdesign.com


0 <= L < oo ?

I built one with 2n3904s and was wondering if I should order some
2n7000s from Mouser to make it more efficient, is all.

Without any more detail than that, no correct answer can be given,
any more than one can answer "how long is a string?".

Post a circuit, and what you're trying to do with it, and we'll try
to help out -- even if we have to start by asking for more detail
yet.

--

Tim Wescott Wescott Design Services http://www.wescottdesign.com



A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/
File:Transistor_Multivibrator.svg

R1=R4=10k R2=R3=10k C1=C2=0.1uF Q1=Q2=2n3904 or 2n7000 (which is why I
asked)

I'm tapping into the node between R4 and Q2's collector to run the gate
of a MOSFET (irf530) to power a blower motor.

Michael


Sorry, R2=R3=60k

If that circuit ever got into a situation where both transistors were
turned on, they would saturate, both their collectors would be sitting at
low voltages, and the base current delivered by R2 and R3 would be
sufficient to keep them saturated.

Moreover, that circuit depends on the base current of a BJT to work: with
a pair of FETs, the average voltage of the gates will rise to equal the
supply voltage, they'll both end up turned on hard, and the circuit won't
work.

You could come up with more elaborate biasing arrangements -- but why?

A 555 will work at 12V -- why not use a 555 and a 12V linear regulator?
You should get plenty of drive to your MOSFET gate, and you'll have a
circuit that won't fail 0.1% of the time, while leaving you unable to
diagnose problems the other 99.9%.

To answer your original question: the base current of the BJT's is small
compared to the power getting burnt in the resistors; the reduced power
consumption (if any) would be lost in the noise of component variations
from unit to unit.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com


Ah, ok. So, to summarize, did I understand this correctly:

1) the astable multivibrator circuit with discrete components requires BJTs to operate properly; the system will not oscillate with FETs

2) there is a 0.1% probability of the system failing to oscillate; use a 555 to avoid this

3) to reduce power consumption, increase R1 and R4

Why... I just get a kick out of using discrete transistors instead of an IC. That's why.

Thanks!

Michael

With 12 volts or so Vcc, you'll be zenering the bipolar b-e junctions,
which is A Bad Thing. Spice will typically not model b-e breakdown.



--

John Larkin Highland Technology, Inc
picosecond timing precision measurement

jlarkin att highlandtechnology dott com
http://www.highlandtechnology.com
 
On Wednesday, December 17, 2014 10:14:16 AM UTC-8, mrda...@gmail.com wrote:
> For an astable multivibrator, would 2n7000 mosfets be more efficient than 2n3904 bjts?

No, considerably less efficient. One cannot get as good power gain from a
MOSFET with very low drain current as one can from a bipolar transistor.
So, for any target transition slew rate, a power advantage will accrue to the
bipolar design variant. You also get lower tolerances on turn-on threshold
voltage (so can design for lower power supply voltages).

To play with these ideas, get LTspice or some similar simulator, and plug
in some device models, and ... start evaluating designs in simulation.
In particular, for power efficiency, crank down the applied voltage or
raise all the resistor values, until something breaks.
 
On Thu, 18 Dec 2014 18:29:27 -0800, John Larkin wrote:

On Wed, 17 Dec 2014 14:37:58 -0800 (PST), mrdarrett@gmail.com wrote:

On Wednesday, December 17, 2014 2:14:30 PM UTC-8, Tim Wescott wrote:
On Wed, 17 Dec 2014 13:47:53 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 1:40:26 PM UTC-8, mrda...@gmail.com
wrote:
On Wednesday, December 17, 2014 12:06:22 PM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:40:20 -0800, mrdarrett wrote:

On Wednesday, December 17, 2014 10:15:32 AM UTC-8, Tim Wescott
wrote:
On Wed, 17 Dec 2014 10:14:10 -0800, mrdarrett wrote:

For an astable multivibrator, would 2n7000 mosfets be more
efficient than 2n3904 bjts?

How long is a string?

--
www.wescottdesign.com


0 <= L < oo ?

I built one with 2n3904s and was wondering if I should order
some 2n7000s from Mouser to make it more efficient, is all.

Without any more detail than that, no correct answer can be
given, any more than one can answer "how long is a string?".

Post a circuit, and what you're trying to do with it, and we'll
try to help out -- even if we have to start by asking for more
detail yet.

--

Tim Wescott Wescott Design Services http://www.wescottdesign.com



A basic astable multivibrator:
http://en.wikipedia.org/wiki/Multivibrator#mediaviewer/
File:Transistor_Multivibrator.svg

R1=R4=10k R2=R3=10k C1=C2=0.1uF Q1=Q2=2n3904 or 2n7000 (which is
why I asked)

I'm tapping into the node between R4 and Q2's collector to run the
gate of a MOSFET (irf530) to power a blower motor.

Michael


Sorry, R2=R3=60k

If that circuit ever got into a situation where both transistors were
turned on, they would saturate, both their collectors would be sitting
at low voltages, and the base current delivered by R2 and R3 would be
sufficient to keep them saturated.

Moreover, that circuit depends on the base current of a BJT to work:
with a pair of FETs, the average voltage of the gates will rise to
equal the supply voltage, they'll both end up turned on hard, and the
circuit won't work.

You could come up with more elaborate biasing arrangements -- but why?

A 555 will work at 12V -- why not use a 555 and a 12V linear
regulator? You should get plenty of drive to your MOSFET gate, and
you'll have a circuit that won't fail 0.1% of the time, while leaving
you unable to diagnose problems the other 99.9%.

To answer your original question: the base current of the BJT's is
small compared to the power getting burnt in the resistors; the
reduced power consumption (if any) would be lost in the noise of
component variations from unit to unit.

--

Tim Wescott Wescott Design Services http://www.wescottdesign.com


Ah, ok. So, to summarize, did I understand this correctly:

1) the astable multivibrator circuit with discrete components requires
BJTs to operate properly; the system will not oscillate with FETs

2) there is a 0.1% probability of the system failing to oscillate; use a
555 to avoid this

3) to reduce power consumption, increase R1 and R4

Why... I just get a kick out of using discrete transistors instead of an
IC. That's why.

Thanks!

Michael

With 12 volts or so Vcc, you'll be zenering the bipolar b-e junctions,
which is A Bad Thing. Spice will typically not model b-e breakdown.

It's actually mentioned in the Wikipedia article he cites. The solution
is protection diodes so the B-E junctions never go more than one diode
drop in reverse -- which means even more parts on the thing.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com
 
On Friday, December 19, 2014 2:29:15 PM UTC-8, whit3rd wrote:
On Wednesday, December 17, 2014 10:14:16 AM UTC-8, mrda...@gmail.com wrote:
For an astable multivibrator, would 2n7000 mosfets be more efficient than 2n3904 bjts?

No, considerably less efficient. One cannot get as good power gain from a
MOSFET with very low drain current as one can from a bipolar transistor.
So, for any target transition slew rate, a power advantage will accrue to the
bipolar design variant. You also get lower tolerances on turn-on threshold
voltage (so can design for lower power supply voltages).

To play with these ideas, get LTspice or some similar simulator, and plug
in some device models, and ... start evaluating designs in simulation.
In particular, for power efficiency, crank down the applied voltage or
raise all the resistor values, until something breaks.

Thanks!
 
On Thursday, December 18, 2014 6:29:36 PM UTC-8, John Larkin wrote:

....

With 12 volts or so Vcc, you'll be zenering the bipolar b-e junctions,
which is A Bad Thing. Spice will typically not model b-e breakdown.



--

John Larkin Highland Technology, Inc
picosecond timing precision measurement

jlarkin att highlandtechnology dott com
http://www.highlandtechnology.com

Ok, so I should stick with 6V max Vcc then?

Absolute max Vebo = 6V, from here.
https://www.fairchildsemi.com/datasheets/2N/2N3904.pdf

I'm surprised I didn't barbecue the 2n3904s then...

Thanks!
 
In article <48379a1lk1q70kd5tqt4gdl60jm7hh2c4v@4ax.com>,
jlarkin@highlandtechnology.com says...
2) there is a 0.1% probability of the system failing to oscillate; use a 555 to avoid this

3) to reduce power consumption, increase R1 and R4

Why... I just get a kick out of using discrete transistors instead of an IC. That's why.

Thanks!

Michael

With 12 volts or so Vcc, you'll be zenering the bipolar b-e junctions,
which is A Bad Thing. Spice will typically not model b-e breakdown.

Which can be corrected in Ltspice :)

I found a couple of circuits in my junk folder that do not work as
planed in the sim afterwards.

I inserted that correction (Spice Directiove). So I think it is
something that should be in the models. oh well..

Jamie
 

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