Amperes squared is energy...

[server]

I is current, R is resistance

Power = IIR

Energy = Power * seconds

R = (kg/Coulomb^2) * meter^2 / second

II = Coulomb squared per second squared

IIR = Power

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second)

The Coulombs cancel out, combine seconds

IIR = kg * (meter^2 / second^3) = Power

II = kg * (meter^2 / second^2) = Energy

Current squared is energy.

QED

 

[bitrex]

On 7/27/2020 12:50 PM, omnilobe@gmail.com wrote:

I is current, R is resistance

Power = IIR

Energy = Power * seconds

R = (kg/Coulomb^2) * meter^2 / second

II = Coulomb squared per second squared

IIR = Power

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second)

The Coulombs cancel out, combine seconds

IIR = kg * (meter^2 / second^3) = Power

II = kg * (meter^2 / second^2) = Energy

Current squared is energy.

QED

If the energy stored in an inductor, 1/2*L*I^2, is joules, then I^2 by
itself can\'t also be joules unless inductance is dimensionless.

Resistance doesn\'t have dimensions of 1/second as your equations on line
8 and 9 imply.

 

[Ricketty C]

On Monday, July 27, 2020 at 12:50:09 PM UTC-4, omni...@gmail.com wrote:

I is current, R is resistance

Power = IIR

Energy = Power * seconds

R = (kg/Coulomb^2) * meter^2 / second

II = Coulomb squared per second squared

IIR = Power

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second)

The Coulombs cancel out, combine seconds

IIR = kg * (meter^2 / second^3) = Power

II = kg * (meter^2 / second^2) = Energy

Current squared is energy.

QED

Where did you come up with this?

R = (kg/Coulomb^2) * meter^2 / second

--

Rick C.

- Get 1,000 miles of free Supercharging
- Tesla referral code - https://ts.la/richard11209

 

[Phil Allison]

Ricketty C wrote:

=================

Where did you come up with this?

R = (kg/Coulomb^2) * meter^2 / second

** Physical quantities have \"dimensions\" - so suspect that is what it hints at. But I believe R is a dimensionless quantity.

That may be the slight of hand you are meant to see.


..... Phil

 

[bitrex]

On 7/27/2020 10:50 PM, Ricketty C wrote:

On Monday, July 27, 2020 at 12:50:09 PM UTC-4, omni...@gmail.com wrote:
I is current, R is resistance

Power = IIR

Energy = Power * seconds

R = (kg/Coulomb^2) * meter^2 / second

II = Coulomb squared per second squared

IIR = Power

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second)

The Coulombs cancel out, combine seconds

IIR = kg * (meter^2 / second^3) = Power

II = kg * (meter^2 / second^2) = Energy

Current squared is energy.

QED

Where did you come up with this?

R = (kg/Coulomb^2) * meter^2 / second

The volt is a joule/coulomb and an amp is a coloumb per second (post
2019 SI redefinition.)

So you can \"define\" an ohm that way by taking the quotient of the two by
Ohm\'s law but it\'s essentially a circular argument, because simplistic
form of Ohm\'s law is empirical, it doesn\'t directly derive from
Maxwell\'s equations in the way say Kirchoff\'s voltage and current laws do.

 

[bitrex]

On 7/27/2020 10:50 PM, Ricketty C wrote:

On Monday, July 27, 2020 at 12:50:09 PM UTC-4, omni...@gmail.com wrote:
I is current, R is resistance

Power = IIR

Energy = Power * seconds

R = (kg/Coulomb^2) * meter^2 / second

II = Coulomb squared per second squared

IIR = Power

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second)

The Coulombs cancel out, combine seconds

IIR = kg * (meter^2 / second^3) = Power

II = kg * (meter^2 / second^2) = Energy

Current squared is energy.

QED

Where did you come up with this?

R = (kg/Coulomb^2) * meter^2 / second

Writing:

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second), that way

is the same as writing: V*I.

Which is surely kg * (meter^2 / second^3), power, but when written V*I
there\'s no justification at all to just drop any of those dimensions.

That is to say starting with the assumption I^2*R is power and then
defining resistance as V/I, is circular

 

[Alan Folmsbee]

On Monday, July 27, 2020 at 11:25:51 AM UTC-10, bitrex wrote:

On 7/27/2020 12:50 PM, omni...@gmail.com wrote:
I is current, R is resistance

Power = IIR

Energy = Power * seconds

R = (kg/Coulomb^2) * meter^2 / second

II = Coulomb squared per second squared

IIR = Power

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second)

The Coulombs cancel out, combine seconds

IIR = kg * (meter^2 / second^3) = Power

II = kg * (meter^2 / second^2) = Energy

Current squared is energy.

QED

If the energy stored in an inductor, 1/2*L*I^2, is joules, then I^2 by
itself can\'t also be joules unless inductance is dimensionless.

Resistance doesn\'t have dimensions of 1/second as your equations on line
8 and 9 imply.

Inductance is dimensionless when studied in detail.
Inductance is about the number of loops. A number has no dimensions.
One Henry is a Weber per ampere. A weber has the same units as an ampere.
A weber is a flux due to current, an ampere is a current. It is just the direction
of flux is perpendicular to the current. They are one phenomenon:
flux is beside a current, amperes are in line with current.

Henry units = 1

weber/amp = 1 unit

 

[Alan Folmsbee]

On Monday, July 27, 2020 at 4:50:39 PM UTC-10, Ricketty C wrote:

On Monday, July 27, 2020 at 12:50:09 PM UTC-4, omni...@gmail.com wrote:
I is current, R is resistance

Power = IIR

Energy = Power * seconds

R = (kg/Coulomb^2) * meter^2 / second

II = Coulomb squared per second squared

IIR = Power

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second)

The Coulombs cancel out, combine seconds

IIR = kg * (meter^2 / second^3) = Power

II = kg * (meter^2 / second^2) = Energy

Current squared is energy.

QED
Where did you come up with this?
R = (kg/Coulomb^2) * meter^2 / second
--

Rick C.

- Get 1,000 miles of free Supercharging
- Tesla referral code - https://ts.la/richard11209
Hello RickC,

Ohm = Volt / Ampere

Volt = Joules per Coulomb

Joules energy equals force times distance

force is mass times meter per second^2

Joule = kg meter^2 / second^2

Volt = (kg/Coulomb) * meter^2 / second^2

Ampere = Coulomb per second

divide volt by amp...

Ohm = (kg/Coulomb^2) * meter^2 / second

 

[bitrex]

On 7/28/2020 12:06 PM, Alan Folmsbee wrote:

On Monday, July 27, 2020 at 11:25:51 AM UTC-10, bitrex wrote:
On 7/27/2020 12:50 PM, omni...@gmail.com wrote:
I is current, R is resistance

Power = IIR

Energy = Power * seconds

R = (kg/Coulomb^2) * meter^2 / second

II = Coulomb squared per second squared

IIR = Power

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second)

The Coulombs cancel out, combine seconds

IIR = kg * (meter^2 / second^3) = Power

II = kg * (meter^2 / second^2) = Energy

Current squared is energy.

QED

If the energy stored in an inductor, 1/2*L*I^2, is joules, then I^2 by
itself can\'t also be joules unless inductance is dimensionless.

Resistance doesn\'t have dimensions of 1/second as your equations on line
8 and 9 imply.

Inductance is dimensionless when studied in detail.
Inductance is about the number of loops. A number has no dimensions.
One Henry is a Weber per ampere. A weber has the same units as an ampere.
A weber is a flux due to current, an ampere is a current. It is just the direction
of flux is perpendicular to the current. They are one phenomenon:
flux is beside a current, amperes are in line with current.

Henry units = 1

weber/amp = 1 unit

Aren\'t you the time-cube guy or somethin\'

 

[Ricketty C]

On Tuesday, July 28, 2020 at 12:27:00 PM UTC-4, bitrex wrote:

On 7/28/2020 12:06 PM, Alan Folmsbee wrote:
On Monday, July 27, 2020 at 11:25:51 AM UTC-10, bitrex wrote:
On 7/27/2020 12:50 PM, omni...@gmail.com wrote:
I is current, R is resistance

Power = IIR

Energy = Power * seconds

R = (kg/Coulomb^2) * meter^2 / second

II = Coulomb squared per second squared

IIR = Power

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second)

The Coulombs cancel out, combine seconds

IIR = kg * (meter^2 / second^3) = Power

II = kg * (meter^2 / second^2) = Energy

Current squared is energy.

QED

If the energy stored in an inductor, 1/2*L*I^2, is joules, then I^2 by
itself can\'t also be joules unless inductance is dimensionless.

Resistance doesn\'t have dimensions of 1/second as your equations on line
8 and 9 imply.

Inductance is dimensionless when studied in detail.
Inductance is about the number of loops. A number has no dimensions.
One Henry is a Weber per ampere. A weber has the same units as an ampere.
A weber is a flux due to current, an ampere is a current. It is just the direction
of flux is perpendicular to the current. They are one phenomenon:
flux is beside a current, amperes are in line with current.

Henry units = 1

weber/amp = 1 unit



Aren\'t you the time-cube guy or somethin\'

I don\'t know about time-cubes, but he was the guy who had come up with a nuclear model based on crystal structures which would \"explain\" magnetism.

--

Rick C.

+ Get 1,000 miles of free Supercharging
+ Tesla referral code - https://ts.la/richard11209

 

[bitrex]

On 7/28/2020 12:28 AM, Phil Allison wrote:

Ricketty C wrote:

=================


Where did you come up with this?

R = (kg/Coulomb^2) * meter^2 / second


** Physical quantities have \"dimensions\" - so suspect that is what it hints at. But I believe R is a dimensionless quantity.

That may be the slight of hand you are meant to see.


.... Phil

What dimensions resistance has depends on how you pick your fundamental
units. in CGS everything is unambiguously derived from the centimeter,
gram, and second and volts/amp oddly ends up having dimensions of
centimeters/second.

In SI volts/amp has dimensions of (kg/Coulomb^2) * meter^2 / second.

The \"sleight of hand\" such as it is is that Power = V*I = I^2*R = V^2/R
are all equivalent ways of saying the same thing, if you start with the
physics fact that V*I has units of power, and the (assumption,
empirically-invented idea that sometimes holds) relation that V = IR.

Substituting the different ways of expressing the power relation into
each other, or any way of expressing V = IR for anything there, results
in no novel information, even if you use the dimensions rather than the
symbols.

So it\'s 9 lines of saying the same thing in different ways and then he
ends up with an equation for power same as he started with. And then on
the last line drops the R and a factor of 1/second and ends up with
dimensions of energy, but with no justification at all to do that.

 

[bitrex]

On 7/28/2020 1:11 PM, bitrex wrote:

On 7/28/2020 12:28 AM, Phil Allison wrote:
Ricketty C wrote:

=================


Where did you come up with this?

R = (kg/Coulomb^2) * meter^2 / second


** Physical quantities have \"dimensions\" - so suspect that is what it
hints at. But I believe R is a dimensionless quantity.

That may be the slight of hand you are meant to see.


....    Phil


What dimensions resistance has depends on how you pick your fundamental
units. in CGS everything is unambiguously derived from the centimeter,
gram, and second and volts/amp oddly ends up having dimensions of
centimeters/second.

In SI volts/amp has dimensions of (kg/Coulomb^2) * meter^2 / second.

The \"sleight of hand\" such as it is is that Power = V*I = I^2*R = V^2/R
are all equivalent ways of saying the same thing, if you start with the
physics fact that V*I has units of power, and the (assumption,
empirically-invented idea that sometimes holds) relation that V = IR.

Substituting the different ways of expressing the power relation into
each other, or any way of expressing V = IR for anything there, results
in no novel information, even if you use the dimensions rather than the
symbols.

So it\'s 9 lines of saying the same thing in different ways and then he
ends up with an equation for power same as he started with. And then on
the last line drops the R and a factor of 1/second and ends up with
dimensions of energy, but with no justification at all to do that.

OP may have looked quickly at this definition on Wikipedia:

<https://en.wikipedia.org/wiki/Ohm#Definition>

and seen that V/A = 1/S and mistaken the large S for seconds rather than
Siemens.

 

[bitrex]

On 7/28/2020 12:35 PM, Ricketty C wrote:

On Tuesday, July 28, 2020 at 12:27:00 PM UTC-4, bitrex wrote:
On 7/28/2020 12:06 PM, Alan Folmsbee wrote:
On Monday, July 27, 2020 at 11:25:51 AM UTC-10, bitrex wrote:
On 7/27/2020 12:50 PM, omni...@gmail.com wrote:
I is current, R is resistance

Power = IIR

Energy = Power * seconds

R = (kg/Coulomb^2) * meter^2 / second

II = Coulomb squared per second squared

IIR = Power

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second)

The Coulombs cancel out, combine seconds

IIR = kg * (meter^2 / second^3) = Power

II = kg * (meter^2 / second^2) = Energy

Current squared is energy.

QED

If the energy stored in an inductor, 1/2*L*I^2, is joules, then I^2 by
itself can\'t also be joules unless inductance is dimensionless.

Resistance doesn\'t have dimensions of 1/second as your equations on line
8 and 9 imply.

Inductance is dimensionless when studied in detail.
Inductance is about the number of loops. A number has no dimensions.
One Henry is a Weber per ampere. A weber has the same units as an ampere.
A weber is a flux due to current, an ampere is a current. It is just the direction
of flux is perpendicular to the current. They are one phenomenon:
flux is beside a current, amperes are in line with current.

Henry units = 1

weber/amp = 1 unit



Aren\'t you the time-cube guy or somethin\'

I don\'t know about time-cubes, but he was the guy who had come up with a nuclear model based on crystal structures which would \"explain\" magnetism.

The power of vooDoo. who do? you do! <https://youtu.be/z6DJmp21vcQ?t=37>

 

[Phil Allison]

Alan Folmsbee wrote:

=====================

** More conjuring tricks going on here that at a magician\'s convention.



> Ohm = Volt / Ampere

** Only in an ideal resistor.


> Volt = Joules per Coulomb

** Only in a resistive circuit.

Joules energy equals force times distance

** Mechanical, kinetic & potential energy are equivalent to electrical Joules when converted to heat.

> force is mass times meter per second^2

** F=mA is a low of motion.

Joule = kg meter^2 / second^2

** Kinetic energy, a moving object\'s heat equivalent.

E =0.5mV^2



> Volt = (kg/Coulomb) * meter^2 / second^2

** When ?

Ampere = Coulomb per second

** That at least is unambiguous.

divide volt by amp...

Ohm = (kg/Coulomb^2) * meter^2 / second

** Context shifting is a fool\'s game.


..... Phil

 

[server]

On Monday, July 27, 2020 at 11:25:51 AM UTC-10, bitrex wrote:

On 7/27/2020 12:50 PM, omnilobe@gmail.com wrote:
I is current, R is resistance

Power = IIR

Energy = Power * seconds

R = (kg/Coulomb^2) * meter^2 / second

II = Coulomb squared per second squared

IIR = Power

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second)

The Coulombs cancel out, combine seconds

IIR = kg * (meter^2 / second^3) = Power

II = kg * (meter^2 / second^2) = Energy

Current squared is energy.

QED


If the energy stored in an inductor, 1/2*L*I^2, is joules, then I^2 by
itself can\'t also be joules unless inductance is dimensionless.

Resistance doesn\'t have dimensions of 1/second as your equations on line
8 and 9 imply.

Hello bitrex,

Error notice:

I made a mistake in the post where I assumed resistance
is per second. I was wrong to skip many steps in the algebra.
I am sorry.

This apology does not change the title assertion :

E = ampere squared

To get the abstract units of measure, where only
meters and seconds are used, the following ideas were used:



Mass equals area: derivation essay

Old science claimed that some units of measure cannot
be factored, such as kilogram, Coulomb, and Farad.
The new science, which I have introduced, factors all
units of measure into meters and seconds.

Outline of the logic and mathematics
____________________________________

1 Understand that electron mobility mu has effectively
the same units of measure as conductance g
(g = 1/R).

2 Use Ohm’s Law and MOSFET current equation to find
that charge is an Area of something. Q = meter^2

3 Understand that the kilogram cannot be isolated
on one side of a formula to be equal to any simple
term on the other side, using standard science.

4 Use energy equation (E = force * distance)
and capacitance definition to bring mass and
capacitance into one formula.

5 Bring Farads and kilograms on one side of a formula.
The other side only has meters and seconds.

6 Logic indicates that mass = meter^2 and
Farad = second^2

Detailed derivation of the Mass=Area fact
_________________________________________

Step 1
I = g * V Ohm’s Law

I = mu * (C/meter^2) * (Vgs-Vt)^2 MOSFET current

I = mu * (C/meter^2) * V^2 simplified MOSFET

C is in Farads, V is in Volts

Set units of g equal to units of mu. That is justified
by observing their definitions.

g = Q * mu * n * A / L

A is area. L is length, n is electrons per cubic meter,
Q is electron charge, g is conductance, mu is mobility.
Notice that time does not affect Q, n, A, or L. Time is
involved in only g and mu.

Step 2
g = mu

I/V = I * meter^2 / (C * V^2)

g = (Coulomb/second) / Volts = Coulomb / Volt * second

mu = velocity/Electric field = (meter/second)/(Volts per meter)

mobility = meter^2 / (Volt * second)

conductance = Coulomb / (Volt * second)

Charge is area, since the properties of
g and mu are the same for making current. They both use time
and voltage. When the other factors are examined, they do not
involve time. (meter, Coulomb do not depend on time).
Q = meter^2 charge equals area, to be used later.

Step 3
In olde science, the kilogram cannot be set equal to anything
other than a kilogram.
mass = mass
kilogram = kilogram
There is no way, if mass is alone on the left, to make any
other equation after cancelling like factors.

Step 4
Q = C * V = Area
Energy = E = force times distance = kg meter^2 / (second^2)
V = E/Q
so
V = kg / second^2 …after cancelling area over charge

Step 5
V = kg/sec^2 = Q/C = meter^2 / C

kg/sec^2 = meter^2/C therefore

mass * capacitance = meter^2 * second^2 “The Composite Formula”

Step 6
Use logic to evaluate “The Composite Formula” to propose ways
that mass can be defined with it.

Choice 1:
mass = meter^2
capacitance = second^2

Choice 2
mass = meter * second
cap = meter * second

Choice 3
mass = meter^2 * second
cap = second

I have selected choice #1 because choice #2 destroys
any reasonableness of formulas such as f=ma. Choice #3 is
not good because then capacitance equals conductance and
mass equals the D diffusion coefficient. Therefore

Mass=Area

so charge=area, from force formula of Mr. Coulomb

so R = 1/second

so

E = ampere squared

I might add more details.
Alan Folmsbee

 

[bitrex]

On 7/28/2020 11:51 PM, omnilobe@gmail.com wrote:

On Monday, July 27, 2020 at 11:25:51 AM UTC-10, bitrex wrote:
On 7/27/2020 12:50 PM, omnilobe@gmail.com wrote:
I is current, R is resistance

Power = IIR

Energy = Power * seconds

R = (kg/Coulomb^2) * meter^2 / second

II = Coulomb squared per second squared

IIR = Power

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second)

The Coulombs cancel out, combine seconds

IIR = kg * (meter^2 / second^3) = Power

II = kg * (meter^2 / second^2) = Energy

Current squared is energy.

QED


If the energy stored in an inductor, 1/2*L*I^2, is joules, then I^2 by
itself can\'t also be joules unless inductance is dimensionless.

Resistance doesn\'t have dimensions of 1/second as your equations on line
8 and 9 imply.

Hello bitrex,

Error notice:

I made a mistake in the post where I assumed resistance
is per second. I was wrong to skip many steps in the algebra.
I am sorry.

This apology does not change the title assertion :

E = ampere squared

To get the abstract units of measure, where only
meters and seconds are used, the following ideas were used:



Mass equals area: derivation essay

Old science claimed that some units of measure cannot
be factored, such as kilogram, Coulomb, and Farad.
The new science, which I have introduced, factors all
units of measure into meters and seconds.

Outline of the logic and mathematics
____________________________________

1 Understand that electron mobility mu has effectively
the same units of measure as conductance g
(g = 1/R).

2 Use Ohm’s Law and MOSFET current equation to find
that charge is an Area of something. Q = meter^2

Using empirically-derived mathematical models based on simplifying
assumptions of the underlying physics, to define fundamental units to be
used to express quantities of the underlying physics itself, is circular

 

[Phil Allison]

bitrex wrote:

================

Using empirically-derived mathematical models based on simplifying
assumptions of the underlying physics, to define fundamental units to be
used to express quantities of the underlying physics itself, is circular

\"** More accurately: \"incestuous\".


..... Phil

 

[bitrex]

On 7/29/2020 2:23 AM, Phil Allison wrote:

bitrex wrote:

================


Using empirically-derived mathematical models based on simplifying
assumptions of the underlying physics, to define fundamental units to be
used to express quantities of the underlying physics itself, is circular



\"** More accurately: \"incestuous\".


.... Phil

Einstein was a genius before he married his first cousin, I\'m not sure
it works the other way.

 

[Cydrome Leader]

Alan Folmsbee <omnilobe@gmail.com> wrote:

On Monday, July 27, 2020 at 4:50:39 PM UTC-10, Ricketty C wrote:
On Monday, July 27, 2020 at 12:50:09 PM UTC-4, omni...@gmail.com wrote:
I is current, R is resistance

Power = IIR

Energy = Power * seconds

R = (kg/Coulomb^2) * meter^2 / second

II = Coulomb squared per second squared

IIR = Power

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second)

The Coulombs cancel out, combine seconds

IIR = kg * (meter^2 / second^3) = Power

II = kg * (meter^2 / second^2) = Energy

Current squared is energy.

QED
Where did you come up with this?
R = (kg/Coulomb^2) * meter^2 / second
--

Rick C.

- Get 1,000 miles of free Supercharging
- Tesla referral code - https://ts.la/richard11209
Hello RickC,

Ohm = Volt / Ampere

Volt = Joules per Coulomb

Joules energy equals force times distance

force is mass times meter per second^2

Joule = kg meter^2 / second^2

Volt = (kg/Coulomb) * meter^2 / second^2

Ok, so what shape is yellow?

 

[RheillyPhoull]

On 29/07/2020 4:36 pm, Cydrome Leader wrote:

Alan Folmsbee <omnilobe@gmail.com> wrote:
On Monday, July 27, 2020 at 4:50:39 PM UTC-10, Ricketty C wrote:
On Monday, July 27, 2020 at 12:50:09 PM UTC-4, omni...@gmail.com wrote:
I is current, R is resistance

Power = IIR

Energy = Power * seconds

R = (kg/Coulomb^2) * meter^2 / second

II = Coulomb squared per second squared

IIR = Power

IIR = (Coul^2 / sec^2) * (kg / Coul^2) * (meter^2 / second)

The Coulombs cancel out, combine seconds

IIR = kg * (meter^2 / second^3) = Power

II = kg * (meter^2 / second^2) = Energy

Current squared is energy.

QED
Where did you come up with this?
R = (kg/Coulomb^2) * meter^2 / second
--

Rick C.

- Get 1,000 miles of free Supercharging
- Tesla referral code - https://ts.la/richard11209
Hello RickC,

Ohm = Volt / Ampere

Volt = Joules per Coulomb

Joules energy equals force times distance

force is mass times meter per second^2

Joule = kg meter^2 / second^2

Volt = (kg/Coulomb) * meter^2 / second^2

Ok, so what shape is yellow?

A slightly bent curved fruit with a black stem, highly valued by simian
animals and homind species.