L
Luiz Gustavo
Guest
What's the difference and put or not, "begin" and "end", in the
"always"?
PS.: Sorry for english.
"always"?
PS.: Sorry for english.
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If you have exactly one statement in your always block, you can omitWhat's the difference and put or not, "begin" and "end", in the
"always"?
PS.: Sorry for english.
Luiz Gustavo wrote:
What's the difference and put or not, "begin" and "end", in the
"always"?
PS.: Sorry for english.
If you have exactly one statement in your always block, you can omit
the begin and end.
always @(posedge clk)
q <= d;
If your always block needs more than one statement, then it needs a
begin and end:
always @(posedge clk) begin
q <= d;
a <= b;
end
If you like named blocks (and I do), then the begin/end is needed:
always @(posedge clk) begin : dflop
q <= d;
end // dflop
The rules are the same for begin/end with always as they are for any
statement where begins/ends may be necessary, for instance if blocks,
etc.
-a
You're welcome. Please don't top-post.Andy Peters escreveu:
Luiz Gustavo wrote:
What's the difference and put or not, "begin" and "end", in the
"always"?
PS.: Sorry for english.
If you have exactly one statement in your always block, you can omit
the begin and end.
always @(posedge clk)
q <= d;
If your always block needs more than one statement, then it needs a
begin and end:
always @(posedge clk) begin
q <= d;
a <= b;
end
If you like named blocks (and I do), then the begin/end is needed:
always @(posedge clk) begin : dflop
q <= d;
end // dflop
The rules are the same for begin/end with always as they are for any
statement where begins/ends may be necessary, for instance if blocks,
etc.
-a
First off al thank you very much...
Yes, and this is explained in any of the several available.VerilogIn this case:
always @(negedge clk)
if (ld)
begin
mem_in [mem_adr_in] <= sri;
mem_adr_in <= mem_adr_in + 1'b1;
end
The struct of "if" is consider as one statement?