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P = I^2 * R (in the wires)advantage of 64 ohm speakers over...8 ohm speakers ?
phil
http://www.google.com/search?&q=voltage-divider+line-loss
Do we need higher voltages to operate them, as power = V^2/R ?
Yes.
They need higher voltage but lower current for a given power output.What is the advantage of 64 ohm speakers over the more traditional
8 ohm speakers. Do we need higher voltages to operate them, as
power = V^2/R
Tia
Do you mean some sort of power opamp. Normal opamps give aboutphil wrote:
What is the advantage of 64 ohm speakers over the more traditional
8 ohm speakers. Do we need higher voltages to operate them, as
power = V^2/R
Tia
They need higher voltage but lower current for a given power output.
If you want to drive a speaker from an opamp output, a 64 ohm speaker
is a much better match to the available voltage and current than an 8
ohm one.
If you hold it to your ear, (as in a cell phone) you might be"John Popelish" <jpopelish@rica.net> wrote in message
news:4086F740.86E16192@rica.net...
phil wrote:
What is the advantage of 64 ohm speakers over the more traditional
8 ohm speakers. Do we need higher voltages to operate them, as
power = V^2/R
Tia
They need higher voltage but lower current for a given power output.
If you want to drive a speaker from an opamp output, a 64 ohm speaker
is a much better match to the available voltage and current than an 8
ohm one.
Do you mean some sort of power opamp. Normal opamps give about
10mA, which will not be enough even for a minature 64ohm speaker, I
believe.