1200mA Power supply and 12Ah battery

J

jaffy james

Guest
hi,
Hi,

I have a mini LCD TV screen which requires a power supply of 12v -
1200mA. I would like to power the device using a battery. As i don't
want to blow up the TV i wanted to make sure the battery I use is
correct.

The voltage is correct, but I don't know what 12Ah means, which are on
the batteries. Can someone clarify this please? Thanks!

Regards,

James
 
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jaffy james <> wrote:

hi,
Hi,

I have a mini LCD TV screen which requires a power supply of 12v -
1200mA. I would like to power the device using a battery. As i don't
want to blow up the TV i wanted to make sure the battery I use is
correct.

The voltage is correct, but I don't know what 12Ah means, which are
on the batteries. Can someone clarify this please? Thanks!

Regards,

James
Hi,
12 Ah means twelve Amp-Hours (i.e. your battery could provide 1 Amp
for 12 hours, or 12 Amps for 1 hour, or whatever. A simple
calculation of 12 Ah divided by 1.2 A (1200mA) gives 10 hours of
runtime on this battery (that's assuming a perfect world and exact
specs - you'll probably get *around* ten hours). No worries about
damaging anything, though.

Chris
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On Sat, 28 Aug 2004 21:04:03 GMT, Chris <chris2k01@hotmail.com> wrote:

-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1

jaffy james <> wrote:

hi,
Hi,

I have a mini LCD TV screen which requires a power supply of 12v -
1200mA. I would like to power the device using a battery. As i don't
want to blow up the TV i wanted to make sure the battery I use is
correct.

The voltage is correct, but I don't know what 12Ah means, which are
on the batteries. Can someone clarify this please? Thanks!

Regards,

James

Hi,
12 Ah means twelve Amp-Hours (i.e. your battery could provide 1 Amp
for 12 hours, or 12 Amps for 1 hour, or whatever. A simple
calculation of 12 Ah divided by 1.2 A (1200mA) gives 10 hours of
runtime on this battery (that's assuming a perfect world and exact
specs - you'll probably get *around* ten hours). No worries about
damaging anything, though.

Chris

Thanks for the info, much appreciated :)

Regards,

James
 

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